1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
STALIN [3.7K]
3 years ago
14

Find the perimeter and area of each figure below.

Mathematics
1 answer:
KonstantinChe [14]3 years ago
6 0
A) Perimeter of Trapezium = 8+5+6+15.5
= 34.5in
Area= 1/2*(a+b)*h
=1/2*(8+15.5)*4
=47in^2

B)Perimeter= 12+6+8.5
=26.5mm

Area=1/2*b*h
=1/2*12*4
=24mm^2
You might be interested in
SOMEONE HELP ME PLSSSSSSSSSSSSSSSSSSS
fomenos

Answer: drag the first one to the fourth one, drag the second one to the first one,drag the third one to the second one,drag the fourth one to the third one.

Step-by-step explanation:if its wrong then im sorry

3 0
3 years ago
5x^(-2)-17x^(-1)+6<br> i’m so confused pls help<br> will give brainliest
laila [671]

It's a quadratic equation in disguise. If you let y=x^{-1}, then y^2=x^{-2}, and we can rewrite the equation as

5y^2-17y+6=0

Solve for y however you like; we get y=\dfrac25 and y=3.

But we want to solve for x, so we have

y=x^{-1}=\dfrac25\implies x=\dfrac52

y=x^{-1}=3\implies x=\dfrac13

5 0
3 years ago
In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
576 = 96 × 6
aliya0001 [1]

Answer:

D

Step-by-step explanation

A.96=6+576

B.576=96+6

C. 96=6×576

D. 576=96×6

5 0
3 years ago
A intercept of 2 and slope of 1/6
Katen [24]

Answer:

what is your question though. if its create an equation, its

y = 1/6x + 2

3 0
3 years ago
Other questions:
  • Helen has 2 winter coats, 4 hats and 3 scarves. How many different outfit combinations does Helen have to chose from?
    5·1 answer
  • when the colony reaches 1385 ants, ivors ant farm will not be big enough for all of them . in how many weeks will the ant popula
    8·1 answer
  • If f(x) =<br> **, what is fa+ 2)?
    11·1 answer
  • Scientific notation of 0.00247
    10·2 answers
  • Question 2!! Someone help ASAP!! I need help!! I don’t Understand
    13·1 answer
  • HELP ASAP!! ILL MARK YOU BRAINLIEST IF CORRECT :)
    6·2 answers
  • What is the angle that forms from the two vectors below? *<br> v= &lt;-12,5&gt;, w= &lt;3,-10&gt;
    8·1 answer
  • Find the slope of the line graphed.
    6·1 answer
  • URGENT! TIMED QUESTION, WILL GIVE BRAINLIEST!
    7·1 answer
  • Y+5.41=8.21 what is y
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!