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Nataliya [291]
3 years ago
12

Measuring the width of a book.

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
5 0
Lol what’s the question
barxatty [35]3 years ago
5 0
What is the problem?
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Please help me u guys!!
QveST [7]
We first need to find the circle formula so we take pi(5)^2 and then we get 78.5 which then we times by the height which is 20 - 5 = 15 then the answer is 1177.5 cm^3
8 0
3 years ago
For 2 events a and b, where p(a) = .5, p(b) = .2 if p(a/b)= .2, find p(a ∩ b)
Drupady [299]
P(A\cap B)=P(A\mid B)\cdot P(B)=0.2\cdot0.2=0.04
5 0
3 years ago
Given the equation 5 + x - 12 = x- 7.
marusya05 [52]

Answer:

Step-by-step explanation:

5 + x - 12 = x- 7 (Add the 5 and -12 to simplify)

x - 7 = x - 7        (notice its the same on both sides of equal sign. Add 7 to both                    sides)

x = x

solution is all real numbers

Part B

5 - 4 - 12 = -4 - 7

-11 = -11

5 + 0 - 12 = 0 - 7

-7 = -7

5 + 5 - 12 = 5 - 7

-2 = -2

8 0
3 years ago
Your engineering firm is asked to specify the maximum load for the elevators in a new building: Each elevator has mass 490 kg wh
steposvetlana [31]

Answer:

a) m =589.734kg

b) n = 8 people (rounded down)

Step-by-step explanation:

The first step is to calculate the maximum load after safety considerations (T_{max}

Since we know that the maximum tension the cables can withstand is 19500N (or 19.5kN). To calculate (T_{max} we multiply this value by \frac{2}{3} (as per the given safety consideration.

Hence

T_{max} = \frac{2}{3} (19500) \\ T_{max} = 13000N

a) Now to find the maximum load in kgs, we use the following formula

(m_{0} + m)(g + a) = T_{max}

Where

m_{0} = mass of elevator

m = maximum load

g = acceleration due to gravity

a = maximum acceleration of elevator

Inputting the values and solving

m_{0} + m)(g + a) = T_{max}\\ (490 + m)(9.8 + 2.24) = 13000\\ 12.04m = 7100.4\\ m = 589.734kg

Hence the maximum load is m =589.734kg

b) To find the number of people (n) we divide the value of m by 70kg

n = 589.734 / 70

n = 8.42 or 8 people

7 0
3 years ago
the price of a stock decreasing rupees 45 per day for the four constitutive days. what was the total change in value of the stoc
Simora [160]

Hi,

45 per day

4 day period

45 * 4 = 180

180 rupees

4 0
3 years ago
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