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kakasveta [241]
3 years ago
8

Continue the pattern 7, 16, 8, 27, 9

Mathematics
1 answer:
levacccp [35]3 years ago
4 0
Hello,

7,4^2\\
8,3^3\\
9,2^4=16

Answer 16
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Mindy lives of a mile away from school. Ron lives as far from school as Mindy. How far is Ron's house from school?
jek_recluse [69]

Answer:

additive comparison

Step-by-step explanation:

4 0
3 years ago
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What is the distance between the point (−10, −2) and the point (−4, −2)?
Reika [66]
6

sorry it's late but hopefully it can help someone else

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3 years ago
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Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x
Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = 3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4

fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

x(x^{2}+x) \neq 0

If x = 0, the function doesn't exist.

x^{2}+x \neq0

x(x+1) \neq0

x+1\neq0

x\neq-1

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

5 0
3 years ago
Find the distance between points (-3,-4) and (1,-2)
Ludmilka [50]

Answer:

√20 or 4.47 ish

Step-by-step explanation:

√(1--3)²+(-2--4)²

√(1+3)²+(-2+4)²

√(4)²+(2)²

√16+4

√20

4.47 ish

(Hopefully this is correct, have a nice day!)

6 0
2 years ago
2x−1/4y=1 solve for y please
Ivan

Answer:

EASY DUBS:

Step-by-step explanation:

2*x-((1/4)*y) = 1 // - 1

2*x-((1/4)*y)-1 = 0

2*x+(-1/4)*y-1 = 0

2*x-1/4*y-1 = 0 // + -1/4*y-1

2*x = -(-1/4*y-1) // : 2

x = (-(-1/4*y-1))/2

x = (1-(-1/4*y))/2

x = (1-(-1/4*y))/2

3 0
2 years ago
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