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Advocard [28]
2 years ago
6

Miss Lincoln has 15 girls and 10 boys in her homeroom if she randomly selects two students to attend the next meeting then what’

s the probability of her picking two boys
Mathematics
1 answer:
Olegator [25]2 years ago
3 0

Answer:

1/4

Step-by-step explanation:

Mrs. Lincoln has 15 girls and 10 boys in her homeroom. She randomly selects two students. The total number of students is 25.

The probability of choosing one girl is:

15 / 25 = 3 / 5

Now, 24 students are left.

The probability of choosing one boy is:

10 / 24 = 5 / 12

Therefore, the probability of choosing one girl and one boy is:

3 / 5 * 5 / 12

= 3 / 12

= 1/4

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GrogVix [38]
If the length of JK is 16.4 miles, it will be diameter of this circle, the radius will be JK/2 = 8.2 miles

As we know the length of circle is 2π*r  in this case r = 8.2

The arc JM is 1/4 length of the whole circle so arc JM = (2π*8.2)*(1/4) = 2π*8.2/4 = π*8.2/2 = π*4.1

if we assume that π=3.14 the answer will be 3.14 * 4.1 = 12.874.... And as the answer needs to be rounded to the nearest tenth it will be 12.874≈12.9

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8 0
3 years ago
The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.35°F and a standard deviati
DochEvi [55]

Answer:

a) 99.97%

b) 65%

Step-by-step explanation:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean of 98.35°F and a standard deviation of 0.64°F.

a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the mean, or between 96.43°F and 100.27°F?

μ - 3σ

98.35 - 3(0.64)

= 96.43°F

μ + 3σ.

98.35 + 3(0.64)

= 100.27°F

The approximate percentage of healthy adults with body temperatures is 99.97%

b. What is the approximate percentage of healthy adults with body temperatures between 97 .71°F and 98.99°F?

within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

μ - σ

98.35 - (0.64)

= 97.71°F

μ + σ.

98.35 + (0.64)

= 98.99°F

Therefore, the approximate percentage of healthy adults with body temperatures between 97.71°F and 98.99°F is 65%

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3 years ago
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11111nata11111 [884]

Answer:

It is not due to the fact it has no variable

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alina1380 [7]
Length times width and that will get you an answer
6 0
2 years ago
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Ratling [72]
The answer is 30,60,90. Because 60 is twice the number 30 and 90 is three times the first number.
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