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iragen [17]
3 years ago
5

One number is 4 more than another. the difference between their squares is 64. what are the numbers

Mathematics
1 answer:
lora16 [44]3 years ago
5 0
We have to set up 2 different equations if we are to solve for 2 unknowns.  The first equation is x = y + 4.  One number (x) is (=) 4 more than another (y + 4).  Since we have determined that x is larger (cuz it's 4 more than y), when we set up their difference, we are going to subtract y from x cuz x is bigger.  The second equation then is x^{2} - y^{2} =64.  In our first equation we said that x = y + 4, so let's sub that value in for x in the second equation: (y+4) ^{2} - y^{2} =64.  Expand that binomial to get y^{2} +8y+16- y^{2} =64.  Of course the y squared terms cancel each other out leaving us with 8y + 16 = 64.  Solving for y we get that y = 6.  Subbing 6 in for y in our first equation, x = 6 + 4 tells us that x = 10. Yay!

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Since C only has two and although it may look like B has three terms, when the letters are joined together like that they are basically just become one big term, so your answer would be A.
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4 years ago
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The curb weight of a new car is 3,347 pounds. How much does the car weigh?
frozen [14]

Answer:

A

Step-by-step explanation:

i think

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4 years ago
Find the angles of 22 and 24 thanks
netineya [11]

Answer:

22) 119

24) 15

Step-by-step explanation:

22) 61 + b = 180              <-- supplementary because on the same line

      b = 119                     <-- subtracted 61 from both sides

24) 87 + (6x + 3) = 180        <-- supplementary because on the same line

     87 + 6x + 3 = 180          <-- take out parantheses

     90 + 6x = 180               <-- add like terms

     6x = 90                         <-- subtracted 90 from both sides

     x = 15                            <-- solve for x by dividing 6 from both sides

6 0
3 years ago
Solve for y in the following equation. x+2y=z​
Galina-37 [17]

Answer:

The Answer:

.

Step-by-step explanation:

x+2y=z

minus x both sides

2y=z-x

divide by 2 both sides

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6 0
4 years ago
Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2
boyakko [2]

<u>Given</u>:

The quadratic equation is x^{2}=-5 x-3

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

x^{2}+5 x+3=0

The solution of the equation can be determined using quadratic formula.

Thus, we get;

x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}

x=\frac{-5 \pm \sqrt{25-12}}{2 }

x=\frac{-5 \pm \sqrt{13}}{2 }

Thus, the two roots of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

Hence, the solutions of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

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3 years ago
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