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A sandwich store charges a delivery fee to bring lunch to an office.
Delivery cost - D
Meatball sandwich cost - M
One office pays $40.50 for 5 meatball sandwiches.
40.50 = 5M + D
Another office pays $66.50 for 9 meat ball sandwiches
66.50 = 9M + D
A. How much does each meatball sandwich add to the cost of delivery?
D = 40.50 - 5M = 66.50 - 9M
40.50 - 5M = 66.50 - 9M
9M - 5M = 66.50 - 40.50
4M = 26.00
M = 6.50
B. What is the delivery fee
D = 40.50 - 5M = 40.50 - 5(6.50) = 40.50 - 32.50 = 8.00
Check
66.50 = 9M + D = 9(6.50) + 8 = 58.50 + 8.00 = 66.50
Answer:
The length of s is 5.1 inches to the nearest tenth of an inch
Step-by-step explanation:
In Δ RST
∵ t is the opposite side to ∠T
∵ r is the opposite side to ∠R
∵ s is the opposite side to ∠S
→ To find s let us use the cosine rule
∴ s² = t² + r² - 2 × t × r × cos∠S
∵ t = 4.1 inches, r = 7.1 inches, and m∠S = 45°
→ Substitute them in the rule above
∴ s² = (4.1)² + (7.1)² - 2 × 4.1 × 7.1 × cos(45°)
∴ s² = 16.81 + 50.41 - 41.1677568
∴ s² = 26.0522432
→ Take √ for both sides
∴ s = 5.10413981
→ Round it to the nearest tenth
∴ s = 5.1 inches
∴ The length of s is 5.1 inches to the nearest tenth of an inch
yes, there are infinitety many polynomial that have exactly one real root just like your example, to determine the real root first let the real root is a, and the complex roots are b±ic the polynomial satisfy
-9x³ + 19x² + 17 = -(x - a)(x - b - ic)(x - b + ic)
9x³ - 19x² - 17 = (x - a)(x - b - ic)(x - b + ic)
4s+7a=861
s+a=168
This can be solved using either elimination or substitution. I am going to use substitution.
Solve s+a=168 for s
s=168-a
Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861
Solve for a
672+3a=861
3a=189
a=63
Substitute 63 for a in s=168-a
s=168-63=105
So, s=105 student tickets and a=63 adult tickets