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Bumek [7]
3 years ago
13

On a game show, Elena is given the choice of three doors: Behind one door is the Grand Prize; behind the others, consolation pri

zes. She picks Door A, and the host, who knows what is behind each door, opens Door B, revealing a consolation prize. The host then offers Elena the opportunity to change her selection to Door C. What should she do?
Mathematics
2 answers:
miv72 [106K]3 years ago
6 0
From the very beginning, each door had a 1/3 probability chance to be holding the grand prize. And the fact that she saw the consolation prize behind one of them does not change this probability.
From the beginning, all doors had equal chances.

Based on this, the answer to your question would be:
She could either accept or not accept the host's offer <span>because the probabilities of the three doors were equal from the beginning.</span>
Maslowich3 years ago
5 0
She should keep her selection of Door A, if its the door she wants, then the Host should open the door for her

Hope this helps :)
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Answer:

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Read 2 more answers
Solve for linear inequality of x - 1 ≥ 4 + x​
defon

\huge\bf{ANSWER:}

\huge\mathrm{No\:solution.}\checkmark

\huge\bf{SOLUTION}:

Hey there, hope you are having a wonderful day! :)

Let's solve this inequality.

First of all, let's move all the numbers to the right, using the \bf{\underline{opposite\:\:operation\:}:

\longmapsto\sf{x-1\geq 4+x

\longmapsto\sf{x\geq 4+x+1

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Now, let's move the variables to the left:

\longmapsto\sf{x-x\geq 5

\longmapsto\sf{0\geq 5

Now, as you can see, we ended up with a false statement. 0 is NOT greater than 5.

Thus, there are no values of x that make the inequality true, and the inequality  has

\bold{No\:solutions.}

Hope you find it helpful.

Feel free to ask if you have any doubts.

\bf{-MistySparkles^**^*

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2 years ago
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andrew-mc [135]
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First, use the distributive property.

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