Answer:
The temperature had dropped by 15 degrees (-15 if you don't want it positive.)
Step-by-step explanation:
Okay!
This is a subtraction problem.
If it started off at 10, and went down to -5, we can do |-5 - 10| (I am using the two bars because it said change.) And we get 15!
The given expression is ![3b^2*(\sqrt[3]{54a}) + 3*(\sqrt[3]{2ab^6})](https://tex.z-dn.net/?f=%203b%5E2%2A%28%5Csqrt%5B3%5D%7B54a%7D%29%20%2B%203%2A%28%5Csqrt%5B3%5D%7B2ab%5E6%7D%29%20)
This can be simplified as :
= ![3*b^2*(\sqrt[3]{27 *2*a}) + 3*(\sqrt[3]{2*a*b^6})](https://tex.z-dn.net/?f=%203%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B27%20%2A2%2Aa%7D%29%20%2B%203%2A%28%5Csqrt%5B3%5D%7B2%2Aa%2Ab%5E6%7D%29%20)
We know that: ![\sqrt[3]{27} = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%203%20%20%20)
Similarly we also can simplify: ![\sqrt[3]{b^6} = b^2](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B3%5D%7Bb%5E6%7D%20%20%3D%20b%5E2%20)
So our expression will look like this:
= ![3*3*b^2*(\sqrt[3]{2a}) + 3*b^2*(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%203%2A3%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20%2B%203%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
= ![9b^2*(\sqrt[3]{2a}) + 3b^2*(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%209b%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20%2B%203b%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
=![\sqrt[3]{2a}*(9b^2 + 3b^2)](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B3%5D%7B2a%7D%2A%289b%5E2%20%2B%203b%5E2%29%20)
=![\sqrt[3]{2a}*(12b^2)](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2a%7D%2A%2812b%5E2%29%20)
This can also be written as:
![12b^2(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%2012b%5E2%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
So the Answer is Option B
Step-by-step explanation:
First we need to find out what they all 3 equal, with multiplication.
5×5=25
10×5=50
20×5=100
In each of these problems, the answer is multiplying itself by 2 in order to get to the next answer. So this is how they are related
Answer:
You sold 20 student tickets.
Step-by-step explanation:
Given that:
Total tickets sold = 27
Total amount collected = $170
Cost of student ticket = $5
Cost of adult ticket = $10
Let,
x be the number of students tickets sold
y be the number of adult tickets sold
x+y = 27 Eqn 1
5x+10y=170 Eqn 2
Multiplying Eqn 1 by 10
10(x+y=27)
10x+10y=270 Eqn 3
Subtracting Eqn 2 from Eqn 3
(10x+10y)-(5x+10y)=270-170
10x+10y-5x-10y=100
5x=100
Dividing both sides by 5

Hence,
You sold 20 student tickets.
Answer:
40
Step-by-step explanation:
8 times 5=40