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4 years ago

1 matrix question help (with picture)

Mathematics

1 answer:

Dominik [7]4 years ago

3 0

Answer:

a = 9/2

Step-by-step explanation:

In order for the equation to be true, the value of the scalar multiplier must be ...

15/3 = -10/-2 = 35/7 = 5

So, you're solving ...

(2/3)a + 2 = 5

(2/3)a = 3 . . . . . . subtract 2

a = 9/2 . . . . . . . . multiply by 3/2

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Chasidy and Shelby went to the candy store. Chasidy bought 5 pieces of fudge and 3 pieces

AlladinOne [14]

Answer:

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Step-by-step explanation:

because we got that 75 cents is for the fudge so they we multiple 75cents w 2 and when you sum it up if it makes the amount they spent then its right

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3 years ago

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Afina-wow [57]

Answer:

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3 years ago

Read 2 more answers

Bryan estimates the cost of a vacation to he $730. the actual cost if the vacation is $850. Find the percent positive or negativ

dusya [7]

Answer:

85.88%

Step-by-step explanation:

put $730 as a fraction with the denominator of $850 and then you get 730/850 then convert it to a decimal and then the decimal to a percent

4 0

3 years ago

If a jar wrench whose handle extends 17 cm from the center of the jar is attached to the lid, what is the minimum force required

Mrac [35]

Answer:

41.5 N

Step-by-step explanation:

Torque is given by:

τ = rF

Solved for force:

F = τ / r

The value of r is the distance from the end of the wrench to the center of the lid, which is:

r = (0.089m / 2) + 0.17m

= 0.2145m

Therefore:

F = 8.9N∙m / 0.2145m

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3 years ago

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Lana71 [14]

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x sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $x= \frac{1}{2}$ and $x= \frac{3}{4}$
y sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $y= \frac{1}{2}$ and $y= \frac{3}{4}$
z sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $z= \frac{1}{2}$ and $z= \frac{3}{4}$ 

Let $f(x,y,z)=\cos{(xyz)}$

$\int\limits \int\limits \int\limits {f(x,y,z)} \, dV \approx f\left( \frac{1}{2} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{3}{4} \right)$
$+f\left( \frac{3}{4} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{3}{4} \right) \\ \\ \approx\cos{ \frac{1}{8} }+\cos{ \frac{3}{16} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{9}{32} }+\cos{ \frac{27}{64} } \\ \\ \approx0.9922+0.9825+0.9825+0.9607+0.9825+0.9607+0.9607 \\ +0.9123 \\ \\ \approx\bold{7.734}$

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3 years ago