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mafiozo [28]
4 years ago
12

1 matrix question help (with picture)

Mathematics
1 answer:
Dominik [7]4 years ago
3 0

Answer:

  a = 9/2

Step-by-step explanation:

In order for the equation to be true, the value of the scalar multiplier must be ...

  15/3 = -10/-2 = 35/7 = 5

So, you're solving ...

  (2/3)a + 2 = 5

  (2/3)a = 3 . . . . . . subtract 2

  a = 9/2 . . . . . . . . multiply by 3/2

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Chasidy and Shelby went to the candy store. Chasidy bought 5 pieces of fudge and 3 pieces
AlladinOne [14]

Answer:

75cents for the fudge while the bubble gum are .50 cents

Step-by-step explanation:

because we got that 75 cents is for the fudge so they we multiple 75cents w 2 and when you sum it up if it makes the amount they spent then its right

6 0
3 years ago
Solve it! Hurry<br> Will mark as brainliest<br> IF U TRY TO get the points free i would report u
Afina-wow [57]

Answer:

A. 3x^2+7x^2+2×3x ×7-84x = 3x^2+7x^2-2×3x×7

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8 0
3 years ago
Read 2 more answers
Bryan estimates the cost of a vacation to he $730. the actual cost if the vacation is $850. Find the percent positive or negativ
dusya [7]

Answer:

85.88%

Step-by-step explanation:

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4 0
3 years ago
If a jar wrench whose handle extends 17 cm from the center of the jar is attached to the lid, what is the minimum force required
Mrac [35]

Answer:

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Step-by-step explanation:

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τ = rF

Solved for force:

F = τ / r

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r = (0.089m / 2) + 0.17m

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Therefore:

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7 0
3 years ago
In the midpoint rule for triple integrals we use a triple riemann sum to approximate a triple integral over a box b, where f(x,
Lana71 [14]
<span>The sub-boxes will have dimensions \frac{2-0}{2} \times \frac{2-0}{2} \times \frac{2-0}{2} =1\times1\times1=1 \ cubic \ units

x sub-intervals are 0 to 1 and 1 to 2. Midpoints are at x= \frac{1}{2} and </span><span>x= \frac{3}{4}
y sub-intervals are 0 to 1 and 1 to 2. Midpoints are at </span><span>y= \frac{1}{2} and </span><span>y= \frac{3}{4}
z sub-intervals are 0 to 1 and 1 to 2. Midpoints are at </span><span>z= \frac{1}{2} and </span><span><span>z= \frac{3}{4}</span>

Let f(x,y,z)=\cos{(xyz)}

\int\limits  \int\limits  \int\limits {f(x,y,z)} \, dV \approx f\left( \frac{1}{2} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{3}{4} \right)
+f\left( \frac{3}{4} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{3}{4} \right) \\  \\ \approx\cos{ \frac{1}{8} }+\cos{ \frac{3}{16} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{9}{32} }+\cos{ \frac{27}{64} } \\  \\ \approx0.9922+0.9825+0.9825+0.9607+0.9825+0.9607+0.9607 \\ +0.9123 \\  \\ \approx\bold{7.734}</span>
5 0
3 years ago
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