We are given the function <span>f(x)=sqrt of (4sinx+2) and is asked to find the first derivative of the function when x is equal to zero.
</span><span>f(x)=sqrt of (4sinx+2)
f'(x) = 0.5 </span><span>(4sinx+2) ^ -0.5 * (4cosx)
</span>f'(0) = 0.5 <span>(4sin0+2) ^ -0.5 * (4cos0)
</span>f'(0) = 0.5 <span>(0+2) ^ -0.5 * (4*1)
</span>f'(x) = 0.5 (2) ^ -0.5 * (4)
f'(x) = -.1.65
X = 9.5/19*30=15 i hope it helps
473x6= 2,838
the answer should be 2,838?
It would take them about 129.9 hours to deliver all of the paper, because if you divide 44 by 52 you get 0.846153... now multiply that by 150 and you get 129.9230... Now round that to the nearest tenth which is 129.9.
Hope this helps :-)
F(-3)=G(-4) the lines meet at that point.