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Natali5045456 [20]
3 years ago
10

Parallel to y + 8x = 4 through (3, 4) ; slope-intercept form

Mathematics
1 answer:
ira [324]3 years ago
3 0

Answer:

y = - 8x + 28

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange y + 8x = 4 into this form

Subtract 8x from both sides

y = - 8x + 4 ← in slope- intercept form

with slope m = - 8

Parallel lines have equal slopes, thus

y = - 8x + c ← is the partial equation

To find c substitute (3, 4) into the partial equation

4 = - 24 + c ⇒ c = 4 + 24 = 28

y = - 8x + 28 ← equation of line

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pentagon [3]

Answer:

12.1

Step-by-step explanation:

76/2π

= 38/π

= 12

3 0
2 years ago
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If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?
Papessa [141]
5/11 = 18/y
5 y = 18 · 11
5 y = 198
y = 198 : 5 
y = 39.6
3 0
2 years ago
Please solve the problem.
Deffense [45]
OK.  I did it, and I have the solution.
_____________________________________

The length of the deck is  (5 + 2x) .
The width of the deck is   (4 + 2x) .

If the deck didn't have that big hole in the middle where the pool is,
then its area would be

                 (5 + 2x) · (4 + 2x) .

When you multiply that all out, you get    Area = 4x² + 18x + 20

and the question tells us that the area of the whole big rectangle is 90 yds² .
So we can write

                                             4x² + 18x + 20  =  90 .

Subtract 90 from each side:    4x² + 18x - 70  =  0
Divide each side by 2 :           2x² + 9x - 35  =  0

You can use the quadratic equation to solve that and find out that
x = 2.5 yards, and that's what the question is asking you.
___________________________________________________

That makes the deck  10 yds high and 9 yds wide.

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3 0
3 years ago
The mean of five numbers is 8. when another number is added the mean is 7. find the number added
sasho [114]

Answer:

\large \boxed{\sf \ \ 2  \ \ }

Step-by-step explanation:

Hello,

<u>The mean of five numbers is 8</u> so we can write

\dfrac{x_1+x_2+x_3+x_4+x_5}{5}=8

<u>When another number is added the mean is 7</u>, let s note x the another number we can write

\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7

From the first equation we can say

x_1+x_2+x_3+x_4+x_5=8*5=40

So the second equation becomes

\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7\\\\ \dfrac{40+x}{6}=7\\\\40 + x = 6*7=42\\\\ x = 42-40 = 2\\

The solution is then 2

Hope this helps

4 0
2 years ago
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Virty [35]

I believe dividing is always the last step.


5 0
3 years ago
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