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Anvisha [2.4K]
3 years ago
15

What is the density of a liquid that has a volume of 20.0 ml and a mass of 330 grams?

Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0
Density=mass/volume
density=330/20
density=16.5g/ml
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Burning 1 kg of coal releases about 3 million joules of energy. If you could use all of the chemical energy to lift another kilo
Katarina [22]

I could lift 3.06 x 10⁵ m high

<h3>Further explanation </h3>

Energy is the ability to do work. Energy can change from one energy to another

Potential energy is the energy that an object has because of its position

The potential energy can be formulated:

Ep = m. g. h

E = potential energy of an object, joule

m = object mass, kg

g = gravity acceleration, m / s²

h = height of an object, m

energy of coal = 3.10⁶ J

mass = 1 kg

g = 9.8 m/s²

\tt h=\dfrac{E}{m.g}\\\\h=\dfrac{3.10^6}{1\times 9.8}=3.06\times 10^5`m

5 0
3 years ago
What is occurring when reactants are mixed and heated and liquid collects in the sidearm of the apparatus
olga55 [171]

When reactants are mixed and heated and liquid collects in the sidearm of the apparatus, a chemical reaction is occurring.

<h3>What is a chemical reaction?</h3>

A chemical reaction is said to occur when reactants are combined to form products. We must note that the formation of products is evidenced by;

  • Appearance of a liquid
  • Appearance of a gas
  • Appearance of a solid

Hence,  when reactants are mixed and heated and liquid collects in the sidearm of the apparatus, a chemical reaction is occurring.

Learn more about chemical reaction:brainly.com/question/22817140

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4 0
2 years ago
Problem page gaseous ethane ch3ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o
iVinArrow [24]

m(\text{CO}_2) = 2.24 \; \text{g}

Ethene react with oxygen at a 2 : 7 molar ratio:

2\; \text{C}_2 \text{H}_6 (g) + 7\; \text{O}_2 (g) \to 6\; \text{H}_2{O} (g) + 4\; \text{CO}_2 (g)

Convert the quantity of each reactant supplied to number of moles of particles:

  • n(\text{C}_2\text{H}_6) = 0.60 \; \text{g} / 28.05 \; \text{g} \cdot \text{mol}^{-1} =  0.0214 \; \text{mol}
  • n(\text{O}_2) = 3.27 \; \text{g} / 32.00 \; \text{g} \cdot \text{mol}^{-1} =  0.102 \; \text{mol}

The question stated not whether both reactants were used up in this process. Thus start by testing the assumption that e.g., ethene was used up while some oxygen gas were left unreacted (ethene as the <em>limiting </em>reagent.) Under this assumption, the relative availability of the two species, n(\text{C}_2 \text{H}_6) /2 and n(\text{O}_2) /7 (as seen in the balanced chemical equation) shall satisfy the relationship

n(\text{O}_2) / 7 - n(\text{C}_2 \text{H}_6) / 2 > 0

In other words,

n(\text{O}_2)/7 > n(\text{C}_2 \text{H}_6)/2

n(\text{C}_2 \text{H}_6) / n(\text{O}_2) < 2/7 \approx 0.286

Evaluating the expression n(\text{C}_2 \text{H}_6) / n(\text{O}_2) with data given in the question yields approximately 0.210 < 0.286, which does satisfy the relationship. Hence the assumption holds and ethene is the limiting reactant.

The quantity of a reactant produced in a chemical reaction is related to its stoichiometric (of relating to proportions) relationship with the limiting reactant (or any of the reactants in case of more than one limiting reactant.) For this scenario, given the molar ratio n(\text{C}_2\text{H}_6) : n( \text{CO}_2) = 2:4,

n(\text{CO}_2) = n(\text{C}_2\text{H}_6) \cdot (2 / 4) = 0.0510 \; \text{mol}

m(\text{CO}_2) = 0.0510 \; \text{mol} \times 44.01 \; \text{g} \cdot  \text{mol}^{-1} = 2.24 \; \text{g}

4 0
3 years ago
Please delete this question. Solved!
joja [24]
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3 years ago
2CO + O2  2CO2
murzikaleks [220]

Answer:

75 L Co2

37.5 L o2

Explanation:

welcome.

3 0
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