Question

Fill in the coefficients that will balance the following reaction a0H2+a1O2=a2H2O

Answer 1

Answer:

Balancing is making the number of atoms of each element same on both the sides  (reactant and product side).

To find the number of atoms of each element we multiply coefficient × subscript  

For example  $5 Mg_1 Cl_2$ contains  

5 × 1 = 5 , Mg atoms and

5 × 2 = 10, Cl atoms  

If there is a bracket in the chemical formula  

For example $3Mg_3 (P_1 O_4 )_2$ we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms  (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So 3 × 3 = 9, Mg atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

So

Let us balance the given equation  

$H_2+O_2>H_2 O$ (Unbalanced)

Reactant Side       # of atoms of each element      Product Side

2                                            H                                           2

2                                           O                                           1

Since O atoms are not balanced on the right side we multiply $H_2 O$ by 2 so the equation changes to

$H_2+O_2 >2H_2 O$

Reactant Side       # of atoms of each element      Product Side

2                                            H                                           4

2                                           O                                           2

Now to balance H atoms on the reactant side we multiply $H_2$ by 2 so we will have

$2H_2+O_2 >2H_2 O$  (Balanced!!!!)

Reactant Side       # of atoms of each element      Product Side

4                                            H                                           4

2                                           O                                           2

Balanced!!!

Answer 2

Answer:

Explanation:

a0H2+a1O2=a2H2O

= 2 H2+1 O2=2 H2O

cheers!