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Vikki [24]
3 years ago
15

2CO + O2  2CO2

Chemistry
1 answer:
murzikaleks [220]3 years ago
3 0

Answer:

75 L Co2

37.5 L o2

Explanation:

welcome.

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The atomic mass of magnesium is the weighted average of the atomic masses of
Debora [2.8K]

Answer:

2. All the naturally occurring isotopes of Mg.

Explanation:

You want to know the atomic mass of the magnesium you use in the lab. That’s “natural” magnesium. So, you must use the weighted average of all the naturally occurring isotopes in natural Mg.

1. and 3. are <em>wrong</em>. You won’t get the correct mass for natural Mg if you use only the artificial isotopes for your calculation.

4. is <em>wrong</em>. You must use all the naturally occurring isotopes. The two most abundant isotopes of Mg account for only 90 % of the atoms. If you ignore the other 10 %, your calculation will be wrong.

6 0
3 years ago
Consider two gases, A and B, are in a container at room temperature. What effect will the following changes have on the rate of
Tcecarenko [31]

Answer:

  1. decrease in temperature , decreases the kinetic movements of the gase molecules as a result decreases the frequency of collisions between gas molecules A and B consequently decreases the rate of reactions of gases A and B
6 0
2 years ago
Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. (Assume standard conditions).
babunello [35]

Answer:

-1.05 V

Explanation:

A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.

Oxidation half equation;

Sn(s) ------> Sn^2+(aq) + 2e

Reduction half equation:

Mn^2+(aq) + 2e ----> Mn(s)

Cell voltage= E°cathode - E°anode

E°cathode= -1.19V

E°anode= -0.14 V

Cell voltage= -1.19 V - (-0.14V)

Cell voltage= -1.05 V

8 0
3 years ago
In the molecule ClF3, chlorine makes three covalent bonds. Therefore, three of its seven valence electrons need to be unpaired.
Kisachek [45]

Answer:

Explanation:

Chlorine has electronic configuration of 2 , 8 , 7

In n = 3 there are 7 electrons out of which 2 are in s , and 5 are in p . But out of 5 electrons in p , one electron jumps into d orbital . so the electronic configuration  becomes as follows

3s^23p_x^23p_y^23p_z^1  = 7

3s^23p_x^23p_y^13p_z^13d_{xy}^1

These orbitals like sp³d hybridise to form 7 degenerate orbitals out of which 2 orbitals contain electrons in pairs and rest three are singly occupied by electrons.( unpaired electrons )

3 0
3 years ago
Which of the following would form a nonelectrolyte solution in water? A. KCl B. NaNO3 C. C6H12O6 D. Cu2SO4
ss7ja [257]
<span>C. C6H12O6

</span>This compound is covalent, and all salts are ionic compounds.
3 0
3 years ago
Read 2 more answers
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