Answer:
The first set of consecutive even integers equals (8 , 6)
The second set is ( - 8 and - 6) which also works.
Step-by-step explanation:
Equation
(x)^2 + (x + 2)^2 = (x)(x + 2) + 52 Remove the brackets on both sides
Solution
x^2 + x^2 + 4x + 4 = x^2 + 2x + 52 Collect the like terms on the left
2x^2+ 4x+ 4 = x^2 + 2x + 52 Subtract right side from left
2x^2 - x^2 + 4x - 2x + 4 - 52 = 0 Collect the like terms
x^2 + 2x - 48 = 0 Factor
(x + 8)(x - 6) = 0
Answer
Try the one you know works.
x - 6 = 0
x = 6
Therefore the two integers are 6 and 8
6^2 + 8^2 = 100
6*8 + 52 = 100
So 6 and 8 is one set of consecutive even numbers that works.
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What about the other set.
x + 8 = 0
x = - 8
x and x + 2
- 8 and -8 + 2 = - 8, - 6
(- 8 )^2 + (- 6)^2 = 100
(-8)(-6) + 52 = 100
Both sets of consecutive numbers work.
Answer:
14 or -22
Step-by-step explanation:
st=18
s=-4
-4+18=14
so t can be at 14
or -4-18=-22
t can be at -22
Answer:
15 of them do not wear glasses
Step-by-step explanation:
20-5=15
Hope this helps. Have a great day :)
Answer:
18
Step-by-step explanation:
pls mark brainliest
idk if this is a joke
The amount if $2950 is invested at an annual rate of 8.4% compounded quarterly is $3486
<h3>
Compound interest</h3>
Compound interest is given by:

where t is the period, r is the rate, P is the initial amount, A is the final amount and n is the times compounded.
Given P = 2950, r = 0.084, n = 4, t = 2, hence:

The amount if $2950 is invested at an annual rate of 8.4% compounded quarterly is $3486
Find out more on Compound interest at: brainly.com/question/24924853