Find the slope of the line shown.

Given the drawing as shown below and that p || a, which of the following cannot be supported by the evidence shown?

masya89 [10]

Answer:

D. <b ≅ <g

Step-by-step explanation:

Given that lines p and q are parallel to each other, therefore the following can be concluded:

✔️<f ≅ <h, this is because they are both Vertical angles.

✔️<d and <h are supplematry, this is because they are same side consecutive interior angles. Consecutive angles are supplematry.

✔️<a and <b are supplematry, this is because they are linear pair angles.

✔️<b cannot be congruent to <g. They are not corresponding angles, nor are they alternate interior angles.

4 0

3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

Plz help me find the measure of each angle indicated. then state the type of angle pair

Makovka662 [10]

19. 60* - a straight line is 180* - the other side which is 120* (supplementary)
20. 132* - the angle below is the same as the other side of this angle, 180* - 48* (same side interior angles)
21. 48* - these are the same angle just in different placements (corresponding angles)
22. 70* - same angles just different placement (alternate interior angles)
23. 85* - these are vertical angles so they’re the same
24. 114* - same angle just different placement (alternate exterior angles)

5 0

3 years ago

What is the volume of the following rectangular prism?

Marianna [84]

Answer:

The volume is 7.9 units

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A triangle has a perimeter of 59cm. If the three sides of the triangle are n, 3n+4, and 4n−1, what is the length of each side?

Elina [12.6K]