Cost price per bottle of juice = $1.10
Selling price per bottle of juice = $2.50
Profit per bottle of juice = $2.50 - $1.10 = $ 1.40
Let B be the number of bottles needed to sell in one day in order to equal its daily costs.
$1200 = $1.40B
857.14285714285714 = B
858 = B (round off to the nearest bottle)
The company must sell 858 bottles of juice in one day in order to equal its daily cost.
Hope this helps! =)
A) How high up the wall does it reach?
Use the Pythagorean theorem
Height^2 + Base^2 = Hyp^2
H^2+ 2^2 = 4^2 Subtract the 2^2 from both sides
H^2 = 4^2 -2^2 Multiply the square roots of both the numbers
H^2= 16 - 4
H^2 = 12
H= sqrt(12) m
Hope this helps
I might be wrong cause I don’t removed this from 4 years ago but it should be 36.4 also plz mark brainlyiest
a) Write an expression to describe the journey of the yellow submarine.
-> ((0 - 40) + 30) - 25
[] Sea level = 0
[] The descend 40 meters = -40
[] After examining the sea, they rose 30 meters = + 30
[] They dove 25 meters to look at an octopus = -25
b) At what depth did they stop to look at the octopus?
-> -35 meters
[] The started at 0 (0), descended 40 (-40), rose 30 (-10), and then sove 25 (-35) to see the octopus
[] Another way to think of this is to simplify our previous expression completely
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer: The required fraction = 
Step-by-step explanation:
Let the required fraction = 
Given: Initial height = 192 inches
Height of ball after second bounce = 
Height of ball after third bounce = 
After the third bounce it is 3 inches off the ground.
So,

Hence, The required fraction = 