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3 years ago

HELP. I WILL GIVE A BRAINLEST PLSSS

Mathematics

2 answers:

Brrunno [24]3 years ago

7 0

The answer is x=+-4 good luck!

Tresset [83]3 years ago

3 0

Solving using the quadratic formula x = +-4

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Can anyone solve this? will give brainliest if correct.

miv72 [106K]

Answer:

See below

Step-by-step explanation:

<u>The missing reasons are:</u>

1. k. Given
2. j. Definition of parallelogram
3. d. Definition of linear pair
4. b. Linear pair postulate
5. e/m. Definition of supplementary
6. g. Same side interior angles theorem
7. e/m. Definition of supplementary
8. a/c. Substitution property of congruence
9. i. Subtraction property of congruence
10. f. Alternate interior angles theorem
11. l. Alternate exterior angles theorem
12. h. Angle congruence postulate

8 0

2 years ago

Read 2 more answers

The amount of time Ricardo spends brushing his teeth follows a Normal distribution with unknown mean and standard deviation. Ric

Papessa [141]

Let $X$ denote the number of minutes spent brushing his teeth, and let $\mu$ be the mean and $\sigma$ the standard deviation for this distribution.

$\mathbb P(X$

The z-score corresponding to this probability is approximately $z=-0.2533$ , which means

$\dfrac{1-\mu}\sigma=-0.2533\iff\mu-0.2533\sigma=1$

Next, (note the sign change)

$\mathbb P(X>2)=0.02\implies\mathbb P(X\le2)=\mathbb P\left(\dfrac{X-\mu}\sigma\le\dfrac{2-\mu}\sigma\right)=0.98$

The corresponding z-score is approximately $z=2.0538$ , so you have

$\dfrac{2-\mu}\sigma=2.0538\iff\mu+2.0538\sigma=2$

Solving the two equations for $\mu$ and $\sigma$ , you'll find that the mean is approximately $\mu=1.1098$ and the standard deviation is approximately $\sigma=0.4334$ .

7 0

3 years ago

To buy a car, Ahmed borrowed $15000 for 3 years at an annual simple interest rate of 9%. how much interest will he pay if he pay

allochka39001 [22]

4,050$ and 19,050 that is your answer

3 0

2 years ago

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$