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zhuklara [117]
3 years ago
6

PLz help ASAP

Chemistry
2 answers:
Andrews [41]3 years ago
6 0
  1. it is at the bottom trust me i did the test
Veseljchak [2.6K]3 years ago
6 0
The answer is C. Hope this helps.
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Plz help me with this question plzzzzz​
LekaFEV [45]

Answer:

6

Explanation:

Formula: Al2O3

If we require 2Al2O3

                       We divide 2 by 3

Sorry for the shadow of phone and fingers.

 

8 0
3 years ago
Perform an on-line search to discover what conditions are favourable to the growth of moss. be sure to include a comment on ph c
Genrish500 [490]
Moss can grow abundantly in an environment with favorable conditions. They usually grow abundantly in cool, moist and dark places. If not dark, they prefer shady areas. Also, they tend to grow in acidic soil with pH range between 5.0-5.5. 
4 0
4 years ago
How is a chemical change different from a physical change?
DaniilM [7]
A physical change<span> in a substance doesn't </span>change<span> what the substance is. In a </span>chemical change<span> where there is a </span>chemical reaction<span>, a new substance is formed and energy is either given off or absorbed.</span>
6 0
4 years ago
A metal oxide with the formula mo contains 15.44% oxygen. in the box below, type the symbol for the element represented by m.
lana66690 [7]

<u>Answer:</u> The element represented by M is Strontium.

<u>Explanation:</u>

Let us consider the molar mass of metal be 'x'.

The molar mass of MO will be = Molar mass of oxygen + Molar mass of metal = (16 + x)g/mol

It is given in the question that 15.44% of oxygen is present in metal oxide. So, the equation becomes:

\frac{15.44}{100}\times (x+16)=16g/mol\\\\(x+16)=\frac{16g/mol\times 100}{15.44}\\\\x=(103.626-16)g/mol\\\\x=87.62g/mol

The metal atom having molar mass as 87.62/mol is Strontium.

Hence, the element represented by M is Strontium.

8 0
3 years ago
Read 2 more answers
A compound has a pka of 7.4. to 100 ml of a 1.0 m solution of this compound at ph 8.0 is added 30 ml of 1.0 m hydrochloric acid.
Monica [59]
 Using the Henderson-Hasselbalch equation on the solution before HCl addition: pH = pKa + log([A-]/[HA]) 8.0 = 7.4 + log([A-]/[HA]); [A-]/[HA] = 4.0. (equation 1) Also, 0.1 L * 1.0 mol/L = 0.1 moles total of the compound. Therefore, [A-] + [HA] = 0.1 (equation 2) Solving the simultaneous equations 1 and 2 gives: A- = 0.08 moles AH = 0.02 moles Adding strong acid reduces A- and increases AH by the same amount. 0.03 L * 1 mol/L = 0.03 moles HCl will be added, soA- = 0.08 - 0.03 = 0.05 moles AH = 0.02 + 0.03 = 0.05 moles Therefore, after HCl addition, [A-]/[HA] = 0.05 / 0.05 = 1.0 Resubstituting into the Henderson-Hasselbalch equation: pH = 7.4 + log(1.0) = 7.4, the final pH.
6 0
3 years ago
Read 2 more answers
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