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harkovskaia [24]
3 years ago
12

Help me answer Number 8 please

Chemistry
1 answer:
aleksandrvk [35]3 years ago
3 0

I and III  because when wearer boil the kinetic energy atoms move faster and the particles break apart which means the space increases instead of decreasing

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Two solutions, initially at 24.60 °C, are mixed in a coffee cup calorimeter (Ccal = 15.5 J/°C). When a 100.0 mL volume of 0.100
-Dominant- [34]

Answer:

∆H°rxn in kJ/mol AgCl = - 59.61 kJ/mol

Explanation:

To solve this question we need to calculate the heat absorbed by the cup calorimeter and by the water in the solutions. We will also need to calculate the amount in moles produced by the reaction since we want to know the ∆H°rxn in kJ/mol AgCl .

mol AgNO₃ = 100 mL x 1L/1000 mL x 0.100 mol/L = 0.01 mol

mol NaCl = 100 mL x 1L/1000 mL x 0.200 mol/L = 0.02 mol

Therefore our limiting reagent is the 0.01 mol AgNO₃ and 0.01 mol AgCl will be produced according to the stoichiometry of the reaction:

AgNO₃ + NaCl ⇒ AgCl + NaNO₃

Heat absorbed by the water:

qw = m(H₂O) x c x ΔT where  m (H₂O) = 200 g ( the density of final solution is  1  g/ml)

c = specific heat of water = 4.18 J/gºC

ΔT = change in temperature =  (25.30 - 24.60 ) ºC = 0.7ºC

qw = 200 g x 4.18 J/gºC x 0.7 ºC = 585.20 J

Heat Absorbed by the calorimeter :

q cal = C cal x  ΔT  = 15.5 J/ºC x 0.7ºC = 10.85 J

Total Heat released by the combustion = qw + qcal = 585.20 J +10.85 J

=  596.05 J

We have to change the sign to this quantity since it is an exotermic reaction  ( ΔT is positive ) and have the ∆Hrxn

∆H rxn  = -596.05 J  

but this  is not what we are being asked since this heat was released by the formation of  0.0100 mol of AgCl so finally  

∆H°rxn = -596.05 J /0.01 mol  = -59,605 J/mol x 1 kJ/1000J = -59.61 kJ/mol

5 0
3 years ago
2. If you add water to dilute a solution, what happens to the molarity of the compound in the
postnew [5]

Each solution has a molaritu, which is equal to the number of moles of a solvent per liter of solutions. When you add water to a solution, the number of moles of the solvent stays the same while the volume increases. Therefore, the molarity decreases; the solution is diluted.

4 0
3 years ago
Hydrogen can reduce copper oxide but not aluminium oxide explain​
Llana [10]

Answer: as copper has lower electrode potential value than hydrogen, it could be reduced by hydrogen.

Explanation: hydrogen has zero reduction potential while Cu has +0.34V and Al has -1.66 V .

SO in electrochemical series who has most negative or less reduction potential value tends to be a good reducing agent than the other.

Hope it helps...

3 0
3 years ago
Read 2 more answers
Less energy was entering Earth's
ololo11 [35]

Answer:

The temperatures on Earth increase

Explanation:

more energy results in more heat.

6 0
2 years ago
Describe how you might determine the m/z and relative abundance of the ions contributing to the peak at 21.876 min
aliya0001 [1]

The m/z and relative abundance of the ions contributed to the peak at 21.876 min. The relative abundance will be 21.876%.

<h3>What is relative abundance?</h3>
  • The proportion of atoms with a particular atomic mass present in an element sample taken from a naturally occurring sample is known as the relative abundance of an isotope.
  • When the relative abundances of an element's isotopes are multiplied by their atomic masses and the results are added up, the result is the element's average atomic mass, which is a weighted average.
  • Chemists often divide the number of atoms in a particular isotope by the sum of the atoms in all the isotopes of that element, then multiply the result by 100 to determine the percent abundance of each isotope in a sample of that element.

To learn more about relative abundance with the given link

brainly.com/question/1594226

#SPJ4

8 0
2 years ago
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