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3 years ago

Help me answer Number 8 please

Chemistry

1 answer:

aleksandrvk [35]3 years ago

3 0

I and III because when wearer boil the kinetic energy atoms move faster and the particles break apart which means the space increases instead of decreasing

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What is the chemical formula for Manganese (IV) biphosphate?

Masja [62]

I believe its the first one because manganese is mn and IV is 4 but the cross thing thing will making it the second one but then you have to simplify making it the first one i hope that helps:)

4 0

3 years ago

How many moles of ethyl alcohol, C2H6O, are in a 16.0 g sample

Anon25 [30]

Moles = mass/molar mass, so n(C2H6O)= 16.0 / (12+12+(1x6)+16)
=0.348 (to correct sig figs)

8 0

3 years ago

What mass of hydrogen sulfide, H2S1, will completely react with 2.00 moles of silver nitrate, AgNO3?

vampirchik [111]

Answer:

34g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H2S + 2AgNO3 —> 2HNO3 + Ag2S

Next, we shall determine the number of mole of H2S required to react with 2 moles of AgNO3.

This is illustrated below:

From the balanced equation above,

We can see that 1 mole of H2S is required to react completely with 2 moles of AgNO3.

Finally, we shall convert 1 mole of H2S to grams. This is shown below:

Number of mole H2S = 1 mole

Molar mass of H2S = (2x1) + 32 = 34g/mol

Mass = number of mole x molar Mass

Mass of H2S = 1 x 34

Mass of H2S = 34g

Therefore, 34g of H2S is needed to react with 2 moles of AgNO3.

6 0

3 years ago

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

3 years ago

formic acid, hcooh, is a weak acid with a ka equal to 1.8×10–4. what is the ph of a 0.0115 m aqueous formic acid solution?

kvasek [131]

The pH of a 0.0115 m aqueous formic acid solution is mathematically given as

pH=2.8424

This is further explained below.

<h3>What is the ph of a 0.0115 m aqueous formic acid solution?</h3>

Generally, the equation for the chemical equation is mathematically given as

HCOOH H^+ + HCOO

$\quad C-C \alpha \quad C \alpha$

$&k a=\frac{c^2 \alpha^2}{e(1-\alpha)}\\\\&K_a=\frac{c \alpha^2}{1-\alpha_4} \quad|\gg\rangle \alpha\\\\&K_a=c \alpha^2\\\\&\alpha=\sqrt{\frac{k a}{c}}\\\\&\alpha=\sqrt{\frac{1.8 \times 10^{-4}}{0.0115}}\\\\&\alpha=\sqrt{156: 527710^{-4}}\\\\&\alpha=\sqrt{1.565 \times 1 \sigma^2}\\\\&\alpha=1.25 \times 10^{-1}\\\\&\alpha=0.125\\$

$&\left[\mathrm{H}^{+}\right]=\mathrm{C \alpha}\\\\&=0.125 \times 0.0115\\\\&=1.4375 \times 10^{-9}\\\\&P=-\log \left[H^{+}\right]\\\\&=-\log \left[1.4375 \times 10^{-3}\right]\\\\&P H=2.8424$