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kondor19780726 [428]
3 years ago
9

Calculate the new volume if a 13.3 L of a gas initially at a pressure of 2.51 atm is subjected to an increase in pressure equiva

lent to 65.0 mmHg.
Chemistry
2 answers:
sergeinik [125]3 years ago
7 0
To answer this item, we assume that the gas being presented is is usual is an ideal values such thath,
                          P(constant + 2(basic control)
                                    P = 2 basic control 
Valentin [98]3 years ago
3 0

Answer:

The value of new volume of the gas will be 390. Liters.

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=2.51 atm\\V_1=13.3 L\\P_2=65.0 mmHg \\V_2=?

1 atm = 760 mmHg

P_2=\frac{65.0}{760 mmHg}=0.0855 atm

Putting values in above equation, we get:

P_1V_1=P_2V_2

V_2=\frac{P_1V_1}{P_2}=\frac{2.51 atm\times 13.3 L}{0.0855 atm}=390. L

The value of new volume of the gas will be 390. Liters.

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Calculate the number of C, H, and O atoms in 1.50 g of glucose, a sugar
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Chemical formula of the glucose: C₆H₁₂O₆

We calculate the molar mass:
atomic mass (C)=12 u
atomic mass (H)=1 u
atomic mass (O)=16 u

atomic weight (C₆H₁₂O₆)=6(12 u)+12(1u)+6(16 u)=72 u+12u+96 u=180 u.
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The molar mass would be: 180 g/ mol


2) we calculate the number of moles of 1.5 g.
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1.5 g----------------------  x

x=(1.5 g * 1 mol) / 180 g≈8.33*10⁻³ moles

we knows that:
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3)We calculate the number of molecules:

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1 mol-----------------------6.022*10²³ molecules of glucose
8.33*10⁻³ moles--------        x

x=(8.33*10⁻³ moles * 6.022*10²³ molecules)/1 mol≈5.0183*10²¹ molecules.

4)We calculate the number of C, H and O atoms:
A molecule of glucose have 6 atoms of C, 12 atoms of H, and 6 atoms of O,
number of atoms of C=(6 atoms/1 molecule)(5.0183*10²¹molecules)≈
3.011*10²²

number of atoms of H=(12 atoms/1 molecule)(5.0183*10²¹ molecules)≈
6.022*10²² .

number of atoms of O=(6 atoms/1 molecule)(5.0183*10²¹ molecules)≈
3.011*10²²

Answer: we have 3.011*10²² atoms of C, 6.022*10²² atoms of H, and 3.011*10²² atoms of O.
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