Question

Calculate the new volume if a 13.3 L of a gas initially at a pressure of 2.51 atm is subjected to an increase in pressure equivalent to 65.0 mmHg.

Answer 1

To answer this item, we assume that the gas being presented is is usual is an ideal values such thath,
                          P(constant + 2(basic control)
                                    P = 2 basic control 

Answer 2

Answer:

The value of new volume of the gas will be 390. Liters.

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=2.51 atm\\V_1=13.3 L\\P_2=65.0 mmHg \\V_2=?$

1 atm = 760 mmHg

$P_2=\frac{65.0}{760 mmHg}=0.0855 atm$

Putting values in above equation, we get:

$P_1V_1=P_2V_2$

$V_2=\frac{P_1V_1}{P_2}=\frac{2.51 atm\times 13.3 L}{0.0855 atm}=390. L$

The value of new volume of the gas will be 390. Liters.