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Lelechka [254]
3 years ago
14

HELPPPPP!!!! ASAP

Mathematics
1 answer:
kolbaska11 [484]3 years ago
4 0

Answer: The projectile reaches its maximum height after 20 seconds.

Step-by-step explanation:

Given the function:

h(t) = -16t^2 + 640t

You can following formula (which gives the x -coordinate of the vertex of the parabola) in order to find after how many seconds the projectile takes to reach its maximum height:

x=t=-\frac{b}{2a}

In this case you can identify that the values of "a" and "b" are:

a=-16\\b=640

Then, substituting values into the formula, you get the following result:

t=-\frac{640}{2(-16)}\\\\t=20

Therefore,based on this, the conclusion is: The projectile reaches its maximum height after 20 seconds.

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In this arithmetic sequence 3, 8, 13, 18, ... which term has the the value 123?
NikAS [45]

Answer:

term 25

Step-by-step explanation:

a is the number added from 3 to 8 is 5(must be constant like 8 to 13 is also 5

b is the zero term so 3-a which is 3-5=-2

7 0
3 years ago
Ms. Jones bought volleyball tickets online. The ticket company charges a
Pachacha [2.7K]

Answer:

3 tickets

Step-by-step explanation:

$23.55-$1.50= $22.05 / $7.35 =  3

3 0
3 years ago
−(7 − 2x) + 7 = −7 solve for x
jekas [21]
First, remove the parentheses

-7+2x+7=-7

Cancel the equal terms.

2x+7=0

Subtract 7

2x= -7

Divide both sides by 2

Final answer is:

X= -3.5
3 0
3 years ago
When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100
ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the <em>future value FV.</em>  

In order to see the rule of formation, let's see the value (in $) for the first few years

<u>End of year 0</u>

1,000

<u>End of year 1(capital + interest + new deposit)</u>

1,000*(1.09)+10  

<u>End of year 2 (capital + interest + new deposit)</u>

(1,000*(1.09)+10)*1.09 +10 =

\bf 1,000*(1.09)^2+10(1+1.09)

<u>End of year 3 (capital + interest + new deposit)</u>

\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)

and we can see that at the end of year 50, the future value is

\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}

The sum  

\bf 1+1.09+(1.09)^2+...+(1.09)^{49}

is the <em>sum of a geometric sequence </em>with common ratio 1.09 and is equal to

\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356

and the future value is then

\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564

The <em>present value PV</em> is

\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62

rounded to the nearest hundredth.

5 0
3 years ago
Tremaine: wants a one bedroom townhouse in a trendy new development downtown; average cost is $145,000 is preapproved for a 4.38
Lina20 [59]

Using the monthly payment formula, it is found that the amount he will have to pay each month is of $649.45.

<h3>What is the monthly payment formula?</h3>

It is given by:

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

In which:

  • P is the initial amount.
  • r is the interest rate.
  • n is the number of payments.

In this problem, considering that the down payment does not count for interest, the parameters are given as follows:

P = 130000, r = 0.0438, n = 30 x 12 = 360.

Then:

r/12 = 0.0438/12 = 0.00365 -> 1+r = 1.00365.

Then the monthly payment is given by:

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

A = 130000\frac{0.00365(1.00365)^{365}}{(1.00365)^{365} - 1}

A = 649.45.

More can be learned about the monthly payment formula at brainly.com/question/2151013

#SPJ1

3 0
2 years ago
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