Answer:
405 Problems
Step-by-step explanation:
- One student in class has 15 problems.
- There are 27 students in the class.
Let's <u>multiply</u> 15 by 27.

<em>In all, there would be 405 problems assigned to the whole class.</em>
Answer:
I would say getting all the them right.
Step-by-step explanation:
There isn't really a way to get more points unless you're getting the questions all correct- So I would say just grind those points!
<h3>
Answer: -1.5</h3>
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Explanation:
Draw a horizontal line from W to the y axis. You should arrive somewhere between -1 and -2. While this isn't exact, it looks like we should arrive right at the middle of -1 and -2; therefore we should get to -1.5
The y coordinate of W is -1.5
Keep in mind this is based on the assumption we reach the halfway point. Unfortunately, W is not on any horizontal grid lines to be able to determine exactly where W is along the y axis.
Answer:
Following are the solution to the given choices:
Step-by-step explanation:
Using chebyshev's theorem
:

In point a)



In point b)

In point c)

In point d)
using standard normal variate


It is in between

And

There for it is in between 5 and 6
Additionally, it is closer to root 25, meaning that it is closer to 5
Rounded to the nearest hundredth is
5.29