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Citrus2011 [14]
3 years ago
15

If EG=67, then EF=? There is a picture below

Mathematics
2 answers:
Vikentia [17]3 years ago
4 0
EF is equal to 32 since
when you combine 3x+7 and 5x-4 you get that x is equal to 8. Plug in 8 to to 3x-7 and you get 3-.
ikadub [295]3 years ago
3 0
If EG=67 we have (3x+7)+(5x-4)=67
let's simplify
67 = (3x + 7) + (5x - 4) \\ 67 = 8x + 3 \\ 64 = 8x \\  \frac{64}{8}  = x \\ 8 = x
now we know x is 8 we can use this to find EF
since EF=3x+7
3(8) + 7 = 24 + 7 = 31
so we have EF is 31!
if.you like my answer please rate Brainliest
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Can someone help me out my grade are bad
ArbitrLikvidat [17]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
The center of a circle is (0, -8). The radius is 9. What is the equation of the circle? Select all that apply.
taurus [48]

Answer:

x² + (y + 8)² = 81

Step-by-step explanation:

Centre (h,k) = (0,-8)

radius (r) = 9

(x - h)² + (y - k)² = r²

(x - 0)² + (y + 8)² = 9²

x² + (y + 8)² = 81

8 0
3 years ago
A cell phone provider classifies its customers as Low users (less than 400 minutesper month) or High users (400 or more minutes
Svet_ta [14]

Answer:

a ) See step by step explanation

b) 50%   and  50%

Step-by-step explanation:

The definition of type of user x is:

if x < 400 minutes  per month  low user

if x > 400 minutes per month  high user

The value for these states are of course yes  or no  ( the user is low or high user)

Then:

if the user is low today  xt  (0)    we have the probability of 80% ( 0,8) of have the user in the same condition and 20% (0,2) of having him or her as high user

xt = 1      

If the user is high today xt (1) is high today we have the probability of 70% ( 0,7) of having  the user in the same condition and 30% (0,3) of having him or her as high user

a) Then we construct the stochastic matrix

 Type of user

         (xt)               xt         xt+1  

      Low (0) or L   0,8        0,2

     High(1)  or H   0,3        0,7

The resulting equation system is:

xt  =  0,8* xt  +  0,2* xt+1

xt+1  = 0,3*xt + 0,7* xt+1

1  =  xt + xt+1

Solving for variables         xt+1  =  1  - xt

xt  = 0,8*xt + ( 1 - xt ) * 0,2

xt - 0,8*xt = 0,2 - 0,2xt

xt - 0,6*xt = 0,2

0,4*xt = 0,2

xt = 0,5       and     xt+1  = 0,5

b)  If in January 0,5  ( 50%) of customesr were  low user

In february  teh % of low user customer wll be

xt  =  0,8* xt  +  0,2* xt+1

0,5 = 0,8*0,5 + 0,2*xt+1

0,5 = 0,4 + 0,2 *xt+1

0,1/0,2 = xt+1        xt+1 = 0,5       or   50%

The same answer for March

7 0
3 years ago
6. If n (E) = 40, n (A) = 22, n (ANB) = 8 and n ((AUB)') = 6, determine n(B)​
Dimas [21]

Answer:

4

Step-by-step explanation:

First n(AUB)=n(E) - n((AUB)')

So n(AUB) = 40 - 6 = 34

Now all u hv to do is use the formulae,

n(AUB) = n(A) + n(B) - n(ANB)

So when u substitute above values,

34=22 + n(B) - 8

So,

n(B) = 4

4 0
3 years ago
While you're in the parking lot, you realize that both the lightbulbs and the light switches
Romashka [77]

Cost of Lightbulb = x

cost of switch is x-8


9x + 4(x-8) = 520.50

Use distributive property:

9x + 4x -32 = 520.50

Simplify:

13x -32 = 520.50

Add 32 to both sides:

13x = 552.50

Divide both sides by 13

X = 42.50


A lightbulb costs $42.50

A switch costs 42.50-8 = $34.50

4 0
2 years ago
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