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3 years ago

A car travels at an average rate of speed of 40 miles per hour for 5 hours. How far does this car travel?

1 answer:

6 0

1 hour = 40 miles.

5 hours = 40 x 5
5 hours = 200 miles.

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Answer: The car can travel 200 miles in 5 hours.
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In rectangle ABCD, AC = -x + 21, BP = -9x + 19, and DP = -y + 5. Find the value of y.

creativ13 [48]

Answer:

y=-5

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The diagonals of a rectangle are equal and bisect each other

$BP=\frac{1}{2}AC$

$DP=BP$

step 1

Find the value of x

$BP=\frac{1}{2}AC$

substitute the given values

$(-9x+19)=\frac{1}{2} (-x+21)$

solve for x

Multiply by 2 both sides

$-18x+38=-x+21$

$18x-x=38-21\\17x=17\\x=1$

step 2

Find the value of y

$DP=BP$

we have

$BP=-9x+19$

$DP=-y+5$

substitute

$-y+5=-9x+19$

substitute the value of x

$-y+5=-9(1)+19\\-y+5=10\\y=5-10\\y=-5$

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3 years ago

What is the square root of 7686.3652736?

Elena-2011 [213]

Answer: 87.6719183867

Step-by-step explanation:

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3 years ago

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Determine which of the following sequences is arithmetic. If the sequence is arithmetic, determine the first term a, an

Ilya [14]

Answer:

the sequence is arithmetic with first term 2 and common different is 2

Step-by-step explanation:

please give me brainlest

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3 years ago

I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.

elena-14-01-66 [18.8K]

Hello,

$m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\$

$cos(30^o)=\dfrac{\sqrt{3} }{2} \\$

In the triangle ABC,

$cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\$

$sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}$

In the triangle ACB,

$cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\$

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3 years ago

On July 9, Mifflin Company receives a $10,200, 90-day, 6% note from customer Payton Summers as payment on account. What entry sh

Ludmilka [50]

Answer:

Since on July 9, Mifflin Company receives a $ 10,200, 90-day, 6% note from customer Payton Summers as payment on account, to determine what entry should be made on July 9 to record receipt of the note the following calculation must be performed :

90 days = 3 months

6/12 x 3 = 1.5%

10,200 x 1,015 = 10,353

Therefore, a debt cancellation for $ 10,200 must be made in the company's accounting records, plus an interest generation for $ 153, which will be justified by the cash income of $ 10,353.

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3 years ago