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raketka [301]
2 years ago
14

How do you tell Side-side-side, Side-Angle-Side, Angle-Angle-Side apart?

Mathematics
1 answer:
Rainbow [258]2 years ago
7 0
They all have abbreviations: Side-Side-Side (SSS), Side-Angle-Side (SAS) and Angle-Angle-Side (AAS). 
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Write 23 in significant notation​
SOVA2 [1]

*I think you meant scientific notation.*

23 in scientific notation would be 2.3 x 10^1.

5 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (1,-5) and (3,5)?
Lana71 [14]

Answer:

a) 5

Step-by-step explanation:

Put them into slope intercept form AKA y=mx+b: -5=m1+b <em>and</em> 5=m3+b

Subtract the equations to get -10=-2m

Divide both sides by two to get: 5=m

Hope this helps! (^-^)

8 0
3 years ago
Jackson is buying a good chain that had an original price of $795 but is advertised as 65% off. Sales tax of 8.50% is applied to
Strike441 [17]
$560.673 is how much that nice chain would cost
7 0
2 years ago
The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui
mixer [17]

Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

s(t) = -16t^2+v_0t+s_0

Where,

s_0 = initial height of the object,

v_0 = initial velocity of the object,

Here,

s_0=400\text{ feet}

v_0=35\text{ feet per sec}

Hence, the height of the ball after t seconds,

s(t)=-16t^2+35t+400

When s(t) = 0,

\implies -16t^2+35t+400=0

t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}

t=\frac{-35\pm \sqrt{1225+25600}}{-32}

\implies t\approx -4.02\text{ or }t\approx 6.21

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

4 0
3 years ago
A process produces batches of a chemical whose impurity concentrations follow a normal distribution with a variance of175. A ran
Tom [10]

Answer:

the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

Step-by-step explanation:

since the variance  S² of the batch follows a normal distribution , then for a sample n of  20 distributions , then the random variable Z:

Z= S²*(n-1)/σ²

follows a χ² ( chi-squared) distribution with (n-1) degrees of freedom

since

S² > 3.10 , σ²= 1.75 , n= 20

thus

Z > 33.65

then from χ² distribution tables:

P(Z > 33.65) = 0.02020

therefore the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

8 0
3 years ago
Read 2 more answers
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