H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
Answer:
C
Step-by-step explanation:
The wanted region(shaded part)..is greater or equal to 2 due to the bold line...so hence the first inequality is....y is greater than or equal to 2
And the second solution....is y is less than x because of the continuous broken line...hence it cant be less than or equal to
Answer:
the whole page????
Step-by-step explanation:
am confusion
Answer:
Step-by-step explanation:
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