(4xy-2y^2)+2y
4-2=2....x will remain y^1-y^2=y^-1
2xy^-1+2y
answer=2x+2y
Answer:
6.703 * 10^8 km
Step-by-step explanation:
<u>Step 1: Subtract</u>
778,500,000 - 108,200,000
<em>670,300,000 km</em>
<em />
<u>Step 2: Convert into scientific notation</u>
670,300,000
<em>6.703 * 10^8</em>
<em />
Answer: 6.703 * 10^8 km
Answer:
4x3y
Step-by-step hmmm ask your teacher
Answer:
Given the following two pair for values x 1 = 5, y 1 = 4 and x 2 = 1, y 2 = .
Calculate the Pythagorean triples associated with each pair
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x 1 = 5, y 1 = 4
Ans:: sqrt[5^2+4^2] = sqrt[41
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and x 2 = 1, y 2 = ?
Ans: r = sqrt[1^2 + ?^2]
