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3 years ago

What is the scale factor of the dilation?

Mathematics

1 answer:

vodomira [7]3 years ago

6 0

I think it's A when shown work it equals to 2 not -1/2

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All of the equations to –32 = k + –19

soldi70 [24.7K]

Answer:

$k = - 13$

Step-by-step explanation:

$- 32 = k - 19 \\ -32 + 19 = k \\ - 13 = k$

8 0

2 years ago

A wildlife service wanted to estimate the number of alligators in a river so they tagged 90 alligators and released them back in

lilavasa [31]

You can solve this with a proportion. If you know that 23 tagged alligators were in a 200 alligator sample, there are 90 tagged alligators in the entire river. Written otherwise:

23/200 = 90/x

and solve for x:

x = 782.608...

So the "best estimate" would be around 783 alligators. Hope that helps! If you liked this answer please rate it as brainliest!! thank you!!!

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4 years ago

Find the lengths of the missing sides. If the length is irrational, round to the nearest tenth.

grigory [225]

Answer: 25

Step-by-step explanation:

8 0

3 years ago

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PLZ, help me with this question.

GenaCL600 [577]

Answer:

The first one

Step-by-step explanation:

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3 years ago

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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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5 0

2 years ago