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Trava [24]
4 years ago
14

Can you help me with question 32? Quadratic Equations

Mathematics
1 answer:
bagirrra123 [75]4 years ago
8 0
Lets x = width
height = 2x - 4

A = 1/2 b h
63 = 1/2 (x)(2x-4)
126 = 2x^2 - 4x
2(x^2 - 2x - 63) = 0
2(x - 9)(x + 7) = 0
x - 9 = 0; x = 9
x + 7 = 0; x = -7

so width = 9
height = 2(9) - 4 = 18 - 4 = 14

answer
width = 9 in
height = 14 in
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3 years ago
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andriy [413]
Suppose that equation of parabola is
y =ax² + bx + c


Since parabola passes through the point (2,−15) then 
−15 = 4a + 2b + c

Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c

Since parabola passes through the point (−3,−5), then 
−5 = 9a − 3b + c


Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5

Solving it we get that 
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Thus, equation of parabola is
y = −2x²− 4x + 1

____________________

Rewriting in the form of 
(x - h)² = 4p(y - k)

i) -2x² - 4x + 1 = y

ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)

iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)

iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)

v) -3(x + 7/6)² = y - 445/36 

vi) (x + 7/6)² = -⅓(y - 445/36) 
(Shifting -⅓ to RHS)

vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p) 


So, after rewriting the equation would be - 

(x + 7/6)² = 4(-⅛)(y - 445/36)

__________________

I hope this is what you wanted.

Regards,
Divyanka♪
__________________
6 0
3 years ago
Read 2 more answers
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stiks02 [169]
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4 0
4 years ago
Find the surface area of regular prism with height 6 cm, if the base of the prism is a Regular quadrilateral with side 4 cm.
marshall27 [118]
A "regular quadrilateral" is a square, so the length and width are both 4 cm. The surface area of a rectangular prism is given by
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The surface area of the prism is 128 cm².


6 0
3 years ago
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