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Trava [24]
3 years ago
14

Can you help me with question 32? Quadratic Equations

Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0
Lets x = width
height = 2x - 4

A = 1/2 b h
63 = 1/2 (x)(2x-4)
126 = 2x^2 - 4x
2(x^2 - 2x - 63) = 0
2(x - 9)(x + 7) = 0
x - 9 = 0; x = 9
x + 7 = 0; x = -7

so width = 9
height = 2(9) - 4 = 18 - 4 = 14

answer
width = 9 in
height = 14 in
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svlad2 [7]

Answer:

k = 73

Step-by-step explanation:

The sum of all the angles in a triangle is  180  degrees.

62 °  +  k +  45 °  =  180

Solve the equation for k

Add  62 °  and  45 °

k +  107  =  180

Move all terms not containing  C  to the right side of the equation.

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4 0
3 years ago
Find the value of h
slamgirl [31]

Answer:

h = 48

because 32 + 3h + 4 = 180

32 + 4 = 36

36 + 3h - 36 = 180 - 36

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h = 48

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3 years ago
Write 1/10 in hundredth,fraction,decimal
Ipatiy [6.2K]
0.10
1/10

Hope I helped!

Let me know if you need anything else!

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3 years ago
Graph the function f(x) = x3 – 5x2 + 6x using the graphing calculator. What are the solutions to the related equation? Check all
Juli2301 [7.4K]

the solutions to the related equation are 0,2,3 .

<u>Step-by-step explanation:</u>

Here we have , function  f(x) = x3 – 5x2 + 6x . Graph of this function is given below  . We need to find What are the solutions to the related equation . Let's find out:

Solution of graph means the  value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !

At x = 0 .

From the graph , at x=0 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 0^3- 5(0)^2 + 6(0)

⇒ f(0) =0

At x = 2 .

From the graph , at x=2 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 2^3- 5(2)^2 + 6(2)

⇒ f(0) =0

At x=3 .

From the graph , at x=3 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 3^3- 5(3)^2 + 6(3)

⇒ f(0) =0

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3 0
3 years ago
If you vertically compress the absolute value parent function, f(x) = x1, by a
777dan777 [17]

Answer:

Step-by-step explanation:

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pls mark as brainliest

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2 years ago
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