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snow_tiger [21]
2 years ago
8

Please help me now help me nowww please

Mathematics
1 answer:
topjm [15]2 years ago
7 0

Answer:

A. 1
B. 3
C. 2
D. 5
E. 4
F. 6

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I need help and answer quick please its due right now <br><br>​
algol [13]

Answer:

will do

Step-by-step explanation:

4 0
2 years ago
The product of two numbers is a ______ of both numbers
qwelly [4]
<h2>The product of two numbers is <em>a,</em>  \sqrt{a} of both numbers.</h2>

Step-by-step explanation:

Given,

The product of two numbers = a

To find, the both numbers = ?

Let the two numbers = x

∴ x × x = a

⇒ x^{2} =  a

⇒ x^{2} =\sqrt{a}^2

Comparing the powers, we get

⇒ x = \sqrt{a}

∴ First number = \sqrt{a} and Second number = \sqrt{a}

Thus, the product of two numbers is <em>a,</em>  \sqrt{a} of both numbers.

5 0
3 years ago
about 60 percent of the human body is composed of water. Write this percent as a fraction in simplest form
gayaneshka [121]
3/5 is it in simplest form.

Put 60 over 100 and then keep reducing until it can go any further.
8 0
3 years ago
The area of a rectangle is 21 yd.² and the length of a rectangle is 1 yard or less than twice the width find the dimensions of t
emmasim [6.3K]

Answer:

length = 6 yards

width = 3.5 yards

Step-by-step explanation:

the length of a rectangle is 1 yard less than twice the width

LEt 'w' be the width of the rectangle

and 'l' be the length of the rectangle

length l = 2 times the width -1

so l = 2w -1

Area of the rectangle = length * width

Area = l * w

we know length is 2w-1  and given area = 21

21 = (2w-1) * w

21= 2w^2 - w

subtract 21 on both sides

0= 2w^2 - w - 21

now solve for 'w'

0= 2w^2 +6w -7w- 21

0 = 2w(w+3)-7(w+3)

0= (2w-7)(w+3)

2w-7 = 0                    and w+3 =0

w = 7/2                            w=-3

width cannot be negative so we ignore w=-3

width w= 3.5

length = 2w-1= 2(3.5) - 1= 7-1=6

length = 6 yards

5 0
3 years ago
5 1/2 + 2 2/3 + 3 2/5=
alex41 [277]
The answer would be 347 over 30(347/30) adding all of those together. I hope that helps!!
4 0
3 years ago
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