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svet-max [94.6K]
3 years ago
7

Big Reward! (Answer the right answer not just comment).

Mathematics
2 answers:
Zina [86]3 years ago
8 0
A: One solution- a=11 b=5
B: Has no solution- a=10 b=5
C: Infinite solution- a=10 b=-8
frosja888 [35]3 years ago
5 0

Answer:

A. a = 0, b = 2

B. a = 10, b = 0

C. a = 10, b = -8

Step-by-step explanation:

2(5x-4)=ax+b

10x - 8 = ax + b

When a = 10, b = -8

This equation becomes true for all x. Hence infinite solutions.

When a = 10, b is not -8,

This equation has no solution.

One possible combination could be:

a = 10, b = 0

When a is not 10,

The two sides of the equation become two non parallel lines which will intersect at one point.

A combination could be:

a = 0, b = 2

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Factorise fully x^2-3x+2
mr Goodwill [35]

Answer:

(x−1)(x−2)

Step-by-step explanation:

The middle number is -3 and the last number is 2.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -3

Multiply together to get 2

Can you think of the two numbers?

Try -1 and -2:

-1+-2 = -3

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Fill in the blanks in

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(x-1)(x-2)

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2.206/1000 = 0.002206

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Answer:

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