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lora16 [44]
3 years ago
7

Rewrite the quadratic funtion from standard form to vertex form. F(x)=2x^2-20x+26

Mathematics
1 answer:
Olegator [25]3 years ago
3 0
F(x)=2(x-5)^2-24 simple algebra
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Solve for x: the quantity of x plus 4 over 3 = 2.
defon

Answer:

x =2

Step-by-step explanation:

(x+4) /3 = 2

Multiply each side by 3

(x+4) /3  *3= 2*3

x+4 = 6

Subtract 4

x+4-4 = 6-4

x =2

8 0
3 years ago
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Put Them in The box They Go in
pav-90 [236]

Answer:

\frac{1}{3}  \times r - 4 \\ 3 \times r - 4 \\  \frac{1}{3}  \times r + 4 \\ 3(r + 4)

5 0
3 years ago
24x10=?? (Please explain in zero the hero or in 4 square..)
Tamiku [17]
240, you just add a zero to 24, I don't know what you mean by zero the hero of 4 square, hope this helps!
6 0
3 years ago
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Graph the first six terms of a sequence where a1 = −10 and d = 3.
Neko [114]

notice the first term is -10, and the common difference is 3, so we add 3 to get the next term.

\bf \begin{array}{cccll}\stackrel{x}{n}&term&\stackrel{y}{value}\\\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\1&a_1&-10\\\\2&a_2&\stackrel{-10+3}{-7}\\\\3&a_3&\stackrel{-7+3}{-4}\\\\4&a_4&\stackrel{-4+3}{-1}\\\\5&a_5&\stackrel{-1+3}{2}\\\\6&a_6&\stackrel{2+3}{5}\end{array}

check the picture below.

8 0
3 years ago
15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

7 0
3 years ago
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