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yan [13]
3 years ago
11

Find the area of the triangle, WILL GIVE BRAINLIEST

Mathematics
2 answers:
Neko [114]3 years ago
8 0

Answer:

10 cm^2

Step-by-step explanation:

area= 1/2 b*h

1/2 (5) (4)

= 1/2 (20)

=10

area= 10cm^2

jenyasd209 [6]3 years ago
5 0

Answer:

a = 10cm²

Step-by-step explanation:

a = (1/2)bh

a = (1/2)(5)(4)

a = 10cm²

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Answer: 10

Step-by-step explanation:

25 + 20= 45

45 + ? = 6:00

A= 15

6 0
2 years ago
Please help me withe this proof as well.​
baherus [9]

- D is the midpoint of AB, E is the midpoint of BC

Answer: A. Given

I left off DB||FC because that's not given.  But we can construct it.

Construct line through C parallel to AB.  Extend DE to intersect and call the meet F.

- DB || FC

By Construction

----

- Angle B congruent to angle FCE

Answer: D. Alternate Interior Angles

We have transversal BC across parallel lines AB and CF, so we get congruent angles ABC and FCB aka FCE

- angle BED congruent to angle CEF

Answer: H. Vertical angles are congruent

When we get lines meeting like this we get the usual congruent and supplementary angles.

- Triangle BED congruent to Triangle CEF

Answer: F. Angle Side Angle

We have BE=CE, DBE=FCE, BED=CEF

- DE congruent to FE and DB congruent to FC

Answer: C. CPTCTF

Corresponding parts ...

- AD congruent to DB and DB congruent to FC therefore AD congruent to FC

Answer: E. Transitive Property of Congruent

Things congruent to the same thing are congruent

- ADFC is a parallelogram

Answer: G.  AD and FC are congruent and parallel

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4 0
2 years ago
How to make 8/11 into and improper fraction
kogti [31]
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7 0
2 years ago
A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the
LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1

The probability that at most 12 ties are too tight is P=1.

5 0
3 years ago
Solve -5(8 – 0.5x) = -2(3 – 0.4x) HELP ASAP
svetlana [45]

Answer:

20

Step-by-step explanation:

if you want a explanation ask for it :)

6 0
2 years ago
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