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3 years ago

Find the area of the triangle, WILL GIVE BRAINLIEST

Mathematics

2 answers:

Neko [114]3 years ago

8 0

Answer:

10 cm^2

Step-by-step explanation:

area= 1/2 b*h

1/2 (5) (4)

= 1/2 (20)

=10

area= 10cm^2

jenyasd209 [6]3 years ago

5 0

Answer:

a = 10cm²

Step-by-step explanation:

a = (1/2)bh

a = (1/2)(5)(4)

a = 10cm²

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chubhunter [2.5K]

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Step-by-step explanation:

25 + 20= 45

45 + ? = 6:00

A= 15

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2 years ago

Please help me withe this proof as well.

baherus [9]

- D is the midpoint of AB, E is the midpoint of BC

Answer: A. Given

I left off DB||FC because that's not given. But we can construct it.

Construct line through C parallel to AB. Extend DE to intersect and call the meet F.

- DB || FC

By Construction

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- Angle B congruent to angle FCE

Answer: D. Alternate Interior Angles

We have transversal BC across parallel lines AB and CF, so we get congruent angles ABC and FCB aka FCE

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Answer: H. Vertical angles are congruent

When we get lines meeting like this we get the usual congruent and supplementary angles.

- Triangle BED congruent to Triangle CEF

Answer: F. Angle Side Angle

We have BE=CE, DBE=FCE, BED=CEF

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Answer: C. CPTCTF

Corresponding parts ...

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Answer: E. Transitive Property of Congruent

Things congruent to the same thing are congruent

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2 years ago

How to make 8/11 into and improper fraction

kogti [31]

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2 years ago

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

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3 years ago

Solve -5(8 – 0.5x) = -2(3 – 0.4x) HELP ASAP

svetlana [45]

Answer:

Step-by-step explanation:

if you want a explanation ask for it :)

6 0

2 years ago