A line segment has (three one two zero) endpoints
The answer is 2
Answer:
4.)
a. x= <u>-6</u> y-3
5
b. x= <u>5</u> y + <u>13</u>
4 4
3.)
a. x= <u>-4y</u> + <u>-8</u>
5 5
b. x=<u> 3</u> y+3
2
Step-by-step explanation:
4.)
a. 5x+6y=-15
Add -6y to both sides.
5x+6y+−6y=−15+−6y
5x=−6y−15
Divide both sides by 5.
5x ÷ 5= -6y-15 ÷5
x= <u>-6</u> y-3
5
b. 4x - 5y=13
Add 5y to both sides
4x−5y+5y=13+5y
4x=5y+13
Divide both sides by 4
4x÷4= 5y+13÷4
x= <u>5</u> y + <u>13</u>
4 4
5.)
a. (5x+4y=-8)
Add -4y to both sides
5x+4y+−4y=−8+−4y
5x=−4y−8
Divide both sides by 5
5x÷5= -4y-8÷5
x= <u>-4y</u> + <u>-8</u>
5 5
b. 2x - 3y = 6
Add 3y to both sides.
2x−3y+3y=6+3y
2x=3y+6
Divide both sides by 2.
2x÷2= 3y+6÷2
x=<u> 3y</u>+3
2
Answer:
3.17% probability of selecting first a green apple and then a nectarine.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
P(a green apple then a nectarine)
This is the probability of selecting first a green apple and then a nectarine.
Initially, there are 8+11+5+12 = 36 fruits, of which 8 are green apples. So 8/36 probability of choosing a green apple.
Now, there are 35 fruits, of which five are nectarines. So 5/35 probability of choosing a nectarine.
Then

3.17% probability of selecting first a green apple and then a nectarine.
(4x - 4) - 3 simplified = 4x -7
As it's already graphed their inetresection point is solution for both functions
- Red one is g(x) as it's linear
- Other one is f(x) as it's modulus
The solution is (1,5)