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4 years ago

At Michael's Craft Store, the paiat set that you

Mathematics

1 answer:

andrew11 [14]4 years ago

8 0

Answer:

Step-by-step explanation:

10 percent off of 26 would be 23.4, then 40 percent off of 23.4 would be 9.36

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Given B(17,5), C(11, -3), D-1, 2), and<br> E(x, -6), find the value of x so that BC || DE.

son4ous [18]

Answer:

$x=-7$

Step-by-step explanation:

Remember that:

Two lines are parallel if their slopes are the same.
Two lines are perpendicular if their slopes are negative reciprocals.
And two lines are neither (a.k.a intersecting) if they are neither parallel nor perpendicular.

We want to find the value of x such that $\overline{BC}\parallel\overline{DE}$ .

Therefore, the slopes of BC and DE must be equivalent.

So, let's find the slope of BC first.

BC)

We can use the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Let B(17, 5) be (x₁, y₁) and let C(11, -3) be (x₂, y₂). Substitute:

$m=\frac{-3-5}{11-17}$

Subtract:

$m=-8/-6=4/3$

So, the slope of BC is 4/3.

DE)

Let D(-1, 2) be (x₁, y₁) and let E(x, -6) be (x, y₂). Substitute:

$m=\frac{-6-2}{x-(-1)}$

We know that the two slopes must be equal. So, the slope of DE must also be 4/3. Substitute 4/3 for m:

$\frac{4}{3}=\frac{-6-2}{x-(-1)}$

Solve for x. Simplify the right:

$\frac{4}{3}=\frac{-8}{x+1}$

Cross multiply:

$4(x+1)=-8(3)$

Multiply on the right:

$4(x+1)=-24$

Divide both sides by 4:

$x+1=-6$

Subtract 1 from both sides:

$x=-7$

So, the value of x is -7.

And we're done!

6 0

3 years ago

Plssssss help me with my test

STatiana [176]

58.5 yards

yea hope this helps

3 0

3 years ago

Suppose a football player kicks a ball and gives it an initial upward velocity of 47 ft/s. Use the formula h(t)= -16t^2+47t+3 wh

statuscvo [17]

Answer:

Step-by-step explanation:

a. when t=0,h=3ft

$h(t)=-16 (t^2-\frac{47}{16}x+(\frac{47}{32} )^2)+\frac{47^2}{32^2} *16+3\\=-16(t-\frac{47}{32})^2+\frac{2209}{64}+3\\=-16(t-\frac{47}{32})^2+\frac{2209+192}{64}\\when~ t=\frac{47}{32}\\h=\frac{2301}{64}\\or~v^2-u^2=2gh\\\\0^2-47^2=2*(-32)h\\or h=\frac{47^2}{64}=\frac{2209}{64} \\height from the ground=\frac{2209}{64} +3=\frac{2301}{64}$