Answer:
A. A
Step-by-step explanation:
there ya go.
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Show me a pic of the problem
Answer:
years 1–4: 62.4 bass per year
years 5–8: 67.6 bass per year
Step-by-step explanation:
If the population in year n is ...
p(n) = 3000·1.02^n
then the average rate of change from year 1 to year 4 is ...
(p(4) -p(1))/(4 -1) = 3000(1.02^4 -1.02^1)/3 = 1020·(1.02^3 -1) ≈ 62.4
The average rate of change for years 1–4 is 62.4 bass per year.
For years 5–8, the rate of change is similarly computed:
(p(8) -p(5))/(8 -5) = 3000(1.02^8 -1.02^5)/3 = 1000·1.02^5·(1.02^3 -1) ≈ 67.6
The average rate of change for years 5–8 is 67.6 bass per year.
To solve this problem, plugin 145 where the y is located and then solve for x
y = -27x +577
145 = -27x +577
145 -577 = -27x
-432 = -27x
-432/-27 = -27x/-27
16 = x
x = 16
After 16 weeks she will have $145 dollars in her account.
Answer:
a pair number whose sum is zero e.g +1-1. used to illustrate addition and subtraction problems. with positive and negative integers.
