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kirza4 [7]
2 years ago
8

James, Alex, and Linda were playing inside of their classroom. One of them broke the window. When their teacher asked who broke

the window, she got these replies:
LINDA: James broke the window!
JAMES: I didn't break it!
ALEX: Neither did I!

Who broke the window?

Mathematics
2 answers:
vichka [17]2 years ago
7 0
I would say Linda too.
alekssr [168]2 years ago
5 0
Linda I’m guessing btw
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A bed is 2400 a discount of 25% was given on the
Brrunno [24]

Answer:

800

Step-by-step explanation:

Given: The selling price of bed is 2400.

          Discount offered is 25%

Lets assume the cost of bed be "x"

Discount offered on the cost price of bed= \frac{25}{100} \times x= 0.25x

∴ Discount offered on the cost price of bed= 0.25x

We know the selling price of bed after discount provided.

Finding the cost price of the bed.

⇒ x-0.25x= 2400

⇒ 0.75x= 2400

cross multiplying both side.

∴ x= \frac{2400}{0.75} = 3200

∴ Cost price of the bed is 3200.

We know selling price of the bed is 2400.

Now, finding the saving.

Saving on the price of bed= Cost price- selling price

Saving= 3200-2400= 800

Hence, saving on the purchase of the bed is 800.

7 0
3 years ago
Which of the following functions has a graph with a vertex that is a translation 5 units horizontally to the right of the vertex
andrezito [222]

Answer:

g(x) = (x -3 )^2 + 2

Step-by-step explanation:

f(x) = (x + 2)^2 + 2

We want to shift this 5 units to the right

The parabola is written in the form

y = a(x-h) ^2 +k  where (h,k) is the vertex

The vertex is at ( -2, 2)

We want to shift it 5 units to the right

-2+5 = 3

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7 0
3 years ago
A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).
maksim [4K]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}

\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}

3 0
2 years ago
5 The graph of a proportional relationship is given along with an equation for a different relationship. Which situation has a g
Shkiper50 [21]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
Help please if you can
r-ruslan [8.4K]

Answer:

i cant

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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