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labwork [276]
3 years ago
12

Beth rode her bike for the following distance each day

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0
Monday: 3 1/4 miles
Tuesday: (3 1/4)(2/3) = 2 1/6 miles
Wednesday: (2 1/6)(2) = 4 1/3 miles
Thursday: (4 1/3)(3/4) = 3 1/4 miles

Add them all up: 13 miles

She has not reached her goal, she needs to ride her bike 2 more miles to reach her goal.
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Solve for t.
vova2212 [387]

Answer:

  -5

Step-by-step explanation:

From your knowledge of multiplication tables, you know that ...

  -35 = -(7×5) = 7×(-5)

Then comparing to the given equation, you realize ...

  t = -5

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Or, you can recognize 7 as the coefficient of t and divide both sides of the equation by that:

  -35/7 = (7t)/7

  -5 = t

5 0
3 years ago
Read 2 more answers
Which of the following is the simplified expression of 2 square root of -16 + the square root of 225 in standard form, a plus b
LuckyWell [14K]

Answer:

<em>The standard form like (a+bi) will be:  15+8i</em>

Step-by-step explanation:

Given expression is:   2\sqrt{-16}+\sqrt{225}

First factoring out -16 as (-1×16) , we will get....

2\sqrt{-1}*\sqrt{16}+\sqrt{225}

Now, replacing \sqrt{-1} as  i .......

2i\sqrt{16}+\sqrt{225}

Finally, simplifying the radicals in the above expression, we will get......

2i*4+15\\ \\ =15+8i

Thus, the standard form like (a+bi) will be:  15+8i

7 0
3 years ago
Read 2 more answers
F(x)= x^2-8x+15
mash [69]
If I'm reading your equations correctly, they are:f(x)=x2-8x+15g(x)=x-3h(x)=f(x)/g(x)The domain of a function is the set of all possible inputs, what we can plug in for our variable.The largest two limitations on domains (other than explicit limitations, like in piecewise functions) are radicals and rational functions. With radical expressions we know that we CANNOT take an even root of a negative number. I don't see that problem here. With rationals we know that we CANNOT divide by zero. So the question becomes, when does h(x) ask us to divide by zero? When is the denominator of h(x) zero?Since the denominator of h(x) is g(x), we cannot let g(x) equal zero. So when does that happen? when x-3=0 or when x=3. I hope you see here that if x=3, then g(x)=0, and so h(x)=f(x)/0, which we CANNOT do. The domain of h(x) is all real numbers not equal to 3. There is more going on here. If you had factored f(x) first, you could have written h(x) in a confusing way:h(x)=( f(x) ) / ( g(x) )h(x)= ( (x-5)(x-3) ) / (x-3) Right here, it looks like (x-3) will cancel out from the top and bottom of your fraction. It does, in a way. The graph of h(x) will behave exactly like the line y=x-5, except that it has a hole in it at x=3 (check this! it's cool!)SOOO, the takeaway is that it is better to determine limitations on your domain BEFORE over-simplifying your equations.
6 0
3 years ago
A bag contains an equal number of blue, green, pink, and red balls. If a ball is chosen at random 200 times, with replacement,
jeyben [28]

Answer: 25%

Step-by-step explanation:

4 0
3 years ago
NEED HELP ASAP!!!!
Genrish500 [490]

Answer:

B) Jill omitted a factor pair, which affected the GCF and factored expression.

Step-by-step explanation:

Jill is factoring the expression 13xy-52y. Her work is shown below.  

Factors of 13xy: 1, 13, x, y  

Factors of 52y: 1, 2, 26, 52, y       OOPSIE  she forgot 4,13

GCF: y

Factored expression: y(13x-52)   13y (x-4)

4 0
4 years ago
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