Answer:
Part 1) 
Part 2) 
Part 3) m∠K=61°
Part 4) m∠L=119°
Part 5) m∠M=61°
Step-by-step explanation:
we know that
In a parallelogram opposite angles and opposite sides are congruent and consecutive angles are supplementary
Part 1) Find the side MN
we know that
MN≅KL ----> by opposite sides
we have
therefore
Part 2) Find the side KN
we know that
KN≅LM ----> by opposite sides
we have
therefore
Part 3) Find the measure of angle K
we know that
m∠K+m∠N=180° ----> by consecutive interior angles
we have
m∠N=119°
substitute
m∠K+119°=180°
m∠K=180°-119°
m∠K=61°
Part 4) Find the measure of angle L
we know that
m∠L≅m∠N ----> by opposite angles
we have
m∠N=119°
therefore
m∠L=119°
Part 5) Find the measure of angle M
we know that
m∠M≅m∠K ----> by opposite angles
we have
m∠K=61°
therefore
m∠M=61°
Answer:
Nothing
Step-by-step explanation:
Nothing is divisible with 0
If the framed picture is shaped like a square and has a 12 square foot surface area, then the answer is yes, it will fit flush against the edge of the crate.
Given Part A:
the volume of the cube = 64 cubic feet
therefore, ∛64 = 4 feet
hence one edge measures 4 feet.
Now for Part B:
the area of the square is 12 square feet.
hence, √12 = 3.36 feet.
we can observe that 3.46<4
which indicates that the area covered by the painting is less than that of the one side of the crate, which makes it easy for the painting to fit in the crate.
Hence the painting will fit a side of crate.
Learn more about Area and Perimeter here:
brainly.com/question/24571594
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Your question was incomplete. Please find the missing content here.
While packing for their cross-country move, the Chen family uses a that has the shape of a cube. PART A PART B If the crate has the volume V = 64 cubic feet, The Chens want to pack a large, framed painting. If an area of 12 square feet , will the painting fit flat what is the length of one edge? the framed painting has the shape of a square with against a side of the crate? Explain.
Answer:
Step-by-step explanation:
Convert the equation of a circle in general form shown below into standard form. Find the center and radius of the circle. Group the x 's and y 's together. Consider the x2 and x terms only. Complete the square on these terms. Replace the x2 and x terms with a squared bracket.
Answer:
Step-by-step explanation:
5x=y+6 --------- equ 1
2x-3y=4 -------- equ 2
5x - 6 = y
y = 5x - 6
substitute in equ 2
2x-3(5x - 6) =4
2x - 3*5x + 3*6 = 4
2x - 15x + 18 = 4
- 13x = 4 - 18
-13x = -14
x = -14/-13
x = 14/13
substitute in equ 1
5*14/13 = y+6
70/13 - 6 = y
y = ( 70 - 78)/13
y = -8/13
