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Nina [5.8K]
3 years ago
10

it says i'm wrong, but i don't see why. could someone explain it? (or maybe the system's just incorrect)

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

i think the answer should be 4y(m+3)/a^2

Step-by-step explanation:

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Answer:what are answer choices

Step-by-step explanation:

4 0
3 years ago
Radical expression of 4d 3/8
DanielleElmas [232]

Answer:

\boxed{4 \sqrt[8]{ {d}^{3} } }

Step-by-step explanation:

=  > 4 {d}^{ \frac{3}{8} }   \\  \\ =   > 4({d}^{3 \times  \frac{1}{8} }) \\  \\  =  > 4( {d}^{3}  \times   {d}^{ \frac{1}{8} } ) \\  \\  =  > 4( {d}^{3}  \times  \sqrt[8]{d} ) \\  \\  =  > 4  \sqrt[8]{ {d}^{3} }

8 0
3 years ago
Help pleaseeeee 20 points
liberstina [14]

It’s the second one!

3 0
3 years ago
Mike Is standing on a ladder that is partly in a hole he starts out on a rung that 6 feet underground climbs up 14 feet the clim
Gala2k [10]

Answer:

-3

mike's final position relative to the ground is 3 feet's underground

Step-by-step explanation:

We take positive value when he is above the ground and then take negative value when he is below or underground

6 feet's underground = -6

He climbs up 14 feet = +14

He climbs down 11 feet = -11

We are required to find his last position relative to ground level

= -6+14-11

= (-6) + (-11) + 14

= -17 + 14

= -3

So we have it that mike's final position relative to the ground is 3 feet's underground

4 0
3 years ago
What is an equation of the line through point (2,1) and perpendicular to the line (-4,1) and (3, -2)?
MissTica

Answer:

Gradient of the line with points (-4,1)&(3,-2) is

(-2-1)÷(3-(-4))=-3/7

Then the equation of that^ line is

Y-1=-3/7(x-(-4))--->y=-3/7x-5/7

Since this^ line is perpendicular to the line you are looking for.the gradient of the line you are looking for is -1÷(-3/7)=7/3

The equation of the line you are looking for is

Y-1=7/3(x-2)--->y=7/3x-11/3

[Cause the line you are looking for passes through the point (2,1) and you found the gradient of this line]

8 0
3 years ago
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