Answer:
they might be since they could be like 16 and if it was raised they couldn't drive any more
Hi
(6-d)(d²-5+3d) = 6d²-30+18d-d³+5d-3d² = -d³+6d²-3d²+18d+5d-30
(6-d)(d²-5+3d) = -d³+3d²+23d-30
Answer: -d³+3d²+23d-30
Step-by-step explanation:
H0: u = 150
H1: u ≠ 150
Total sum = 15933.24
N = 100
Mean = 15933.24/100
= 159.3324
σ² = 25954.03 - (159.3324)²/100
σ² = 556.213
σ = √556.213
σ = 23.8162
Testing hypothesis
t = (bar x - u)/ σ/√n
= 159.3324-150/23.8162/√100
= 3.91
We will have a p value of 0.02
0.0002 < 0.01
We reject null hypothesis at 1% level of significance
C. Mean = 159.3324
Se= 2.3936
Df = 100-1 = 99
Critical value at 0.01 = +-2.626
T = x-u/s.e
= -2.626 =( x -150)/2.3936
When we cross multiply and solve this
X = 143.714 for the lower tail
2.626 = (x-159)/2.3936
= 156.286 for upper tail.
We therefore reject H0 at
Bar X <= 143.71
Bar X >= 156.286
At 10%
Critical t = 1.660
-1.660 = (x - 150)/2.3936
Solving this ,
X =146.02 at the lower tail
1.660 = (x-150)/2.3936
X = 153.97
We reject H0 at
X<= 146.03
X>=153.97
Answer:
99
Step-by-step explanation:
99 because x= 10 so 10 times 10 is 100 - 1 will = 99
