Ask question

Ask question

All categories

3 years ago

10

Plesssssssss help with my math problem

2 answers:

OleMash [197]3 years ago

3 0

We don't have a problem to work with... Did you try attaching a picture or something?

Taya2010 [7]3 years ago

3 0

We need the question. Or a picture

You might be interested in

12 POINTS<br>Simplify i38. <br> i <br> −1 <br> −i <br> 1

Karolina [17]

Are you sure you've copied down the original problem exactly as given? i38 = 38i can't be simplified. Perhaps you meant i^38, which is a different matter.

Note that i^38 = i^32 * I^4 * I^2.

Note that i^0, i^4, i^8, etc., all equal 1. Therefore,

i^38 = (1)(1)i^2 = 1*(-1) = -1 (answer)

3 0

3 years ago

Read 2 more answers

Select the correct answer.

antoniya [11.8K]

Answer:

B

Step-by-step explanation:

No solutions

8 0

3 years ago

Read 2 more answers

A circular running track is 1/4 of a mile long Elena runs this track completing each lap in 1/20 of an hour what is her speed

PSYCHO15rus [73]

Answer:

The speed is equal to $5\frac{mi}{h}$

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

x------> the distance in miles

y-----> the time in hours

s----> the speed in mph

so

$s=\frac{x}{y}$

In this problem we have

$x=(1/4)\ mi$

$y=(1/20)\ h$

substitute

$s=\frac{(1/4)}{(1/20)}=20/4=5\frac{mi}{h}$

3 0

2 years ago

What is 8 minus the quotient of 15 and y

DerKrebs [107]

You would end up with an equation of 8 - y/15.

6 0

3 years ago

Pani-rosa [81]

The vertices of the triangle are the points where any pair of lines intersect.

We start by setting up the system

$\begin{cases}y=-x+2\\y=2x-1 \end{cases} \iff -x+2=2x-1 \iff 3x=3 \iff x=1$

Using one of the two equations we can derive the correspondent y value:

$f(x)=-x+2 \implies f(1)=-1+2 = 1$

So, one vertex is (1, 1)

We choose the other two pairs of lines to find the other vertices:

$\begin{cases}y=-x+2\\y=x-2 \end{cases} \iff -x+2=x-2 \iff x=2 \implies y = 0$

$\begin{cases}y=x-2\\y=2x-1 \end{cases} \iff x-2=2x-1 \iff x=-1 \implies y=-3$

So, the three vertices are (1, 1), (2, 0), (-1, -3).

8 0

2 years ago