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dedylja [7]
3 years ago
7

Multiply and simplify.2x^4yx times 6xy^2z^3

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0

Answer:

The answer is:

12x^6y^3z^3

Step-by-step explanation:

When we are asked to multiply the two terms or the polynomials, then we can use the formula:

\:a^b\cdot \:a^c=a^{b+c}\\

So we can so thing only for the same base expressions or the like terms. Now, there are other techniques too, to find the multiplication of two or more than two terms.

Now, the given multiplication form is:  

\left(2x^4yx\right)\left(6xy^2z^3\right)\\

So we have:

\left(2x^4yx\right)\left(6xy^2z^3\right)\\=2y\cdot \:6x^{4+1+1}y^2z^3\\=12x^6y^3z^3

Thus it is the required simplified form.

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love history [14]

y=-x

slope for perp line = 1

2y=-x+6

y=-1/2x +3

slope for perp line = 2

15.

i don’t wanna do all sorry it’s a lot of work so i’ll tell u how to do it instead. first write it in slope intercept form which is

y-y1=m(x-x1)

it’s parallel which means it shares the same slope. if it’s perpendicular it would be opposite reciprocals so for -3/2 the perp slope would be 2/3.

the line is

y+1=3/4(x-4)

we distribute the 3/4 so it’s now

y+1=3/4x-3

then we subtract the 1

y=3/4x-4 is the equation boom done

6 0
2 years ago
Joshua walked 14 feet down the hall of his house to get the door he continued in a straight line out the door and across the yar
AleksandrR [38]

Answer:

Joshua walked 48 feet in total.

Step-by-step explanation:

To find the total distance we need to sum every distance that he walked. We have:

- First: Joshua walked down the hall to the door = 14 feet

- Second: He continued in a straight line out the door and across the yard to the mailbox = 24 feet

- Third: He came straight back across the yard and stopped to pet his dog = 10 feet

Hence, the total distance is:

d_{T} = d_{1} + d_{2} + d_{3} = 14 ft + 24 ft + 10 ft = 48 ft

Therefore, Joshua walked 48 feet in total.

I hope it helps you!

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3 years ago
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tatuchka [14]

Answer:

THE answer is 4% because u divide

5 0
3 years ago
Given that sin(30)=1/2 and cos(30)=(sqrt3)/2, use trigonometric identities to find the value of cot(30)
Anit [1.1K]

<u>Your question: </u>given that sin(30)=1/2 and cos(30)=(sqrt3)/2, use trigonometric identities to find the value of cot(30)

The correct answer would be D \sqrt{3}

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3 years ago
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Answer:

Equation: -3x + 18

Hope this helps!

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