Answer:
negative numbers can't have a square root it would have to be imaginary
Step-by-step explanation:
Answer:
<h2>
<em>1×10⁻⁴ and 9.8×10⁵</em></h2>
Step-by-step explanation:
The standard form of writing a scientific notation is expressed as 
where a, b and n are integers. Note that a, b and n cannot be a fraction. When writing in scientific notation, the value of 'a' must not be equal to zero and it must not be a 'two digits values' but just 'a digit value'.
<em>Based on the above conclusion, the following numbers are correctly written in scientific notation.</em>
<em>1×10⁻⁴ and 9.8×10⁵</em>
- The expression 10.8×10 −3 is not correctly written because the value of a on comparison is a two digits number i.e 10.
- Also, 0.54×10^6 is not correctly written because a is zero on comparison
- 7.6×10 2.5 is not correctly written because the power is a decimal number i.e 2.5. We must only have an integer as the degree.
Answer:
b. 256
Step-by-step explanation:
Data:
W= 8
L= 8
H= 8
soln:
firstly the formula of lateral area is
LSA = (2W+2L) H
therefore:
LSA = (2×8+2×8) 8
LSA = (16+16) 8
LSA = (32) 8
LSA = 256
Answer:37
Step-by-step explanation:You multiply the ones that are in the parenthes
Answer:
(−=|>)=∑(−=,=|>)=∑(−=|=,>)(=|>)=∑(−=|>)(=|>)
Step-by-step explanation:
Substitutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+
1−x
2
∣=
2
(2x
2
−1)\Leftright∣cos\alp+sin\alp∣=
2
(2cos
2
\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N
2
cos(\alp−
4
π
)∣=N
2
cos(2\alp)\Right\alp∈[0;
4
π
]∪[
4
3π
;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;
4
π
]
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−
4
π
)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[
4
3π
;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−
4
π
)=cos(2\alp)…
