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3 years ago

What are the solutions for x when y is equal to 0 in the following quadratic

Mathematics

1 answer:

lawyer [7]3 years ago

7 0

Answer:

D) x = -12 or x = 2

Step-by-step explanation:

The given quadratic equation is:

$y=x^2+10x-24$

When y=0, we obtain:

$x^2+10x-24=0$

We split the middle term with -2, 12 because their product is is -24 and their sum is 10.

$x^2-2x+12x-24=0$

We factor by grouping to obtain:

$x(x-2)+12(x-2)=0$

$(x-2)(x+12)=0$

Either $(x-2)=0$ or $(x+12)=0$

Either $x=2$ or $x=-12$

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Greta wants to make 5 pounds of a nut mix using peanuts and cashews. Her budget requires the mixture to cost her $6 per pound. P

Vinil7 [7]

Answer:

3 pounds of peanuts and 2 pounds of cashews

Step-by-step explanation:

Let x be the pounds of peanuts and y be the pounds of cashews

Greta wants to make 5 pounds of a nut mix using peanuts and cashews.

So, $x+y=5$ ----- A

Cost of 1 pound of peanuts = $4

Cost of x pounds of peanuts = 4x

Cost of 1 pound of cashews = $9

Cost of y pounds of cashews = 9y

Her budget requires the mixture to cost her $6 per pound

So, cost of mixture of x pounds of peanuts and y pounds of cashews is 6(x+y)

So, $4x+9y=6(x+y)$ --- B

Plot A and B

$x+y=5$ ---Blue

$4x+9x=6(x+y)$ ---Green

Refer the attached figure

Intersection point = (x,y)=(3,2)

Hence she should use 3 pounds of peanuts and 2 pounds of cashews

6 0

3 years ago

Solve by elimination 3×+11y=4,-2×-6y=0

gizmo_the_mogwai [7]

3x + 11y = 4

2x + 6y = 0

I got
15/2, -5/4

6 0

3 years ago

Plz answer!! only if you are correct. don’t answer just for points :)

Ann [662]

Answer

Step-by-step explanation:

Both 1 and 2 equel up to 90 degrees

so to find x for 1 and 2 you would simplify the equations

90 = 6x - 3

and

90= 3x - 6

simplify them and you wil get the answers you want

another way to do it is combining the two and solve.

90 = 9x - 9

Just simplify :)

8 0

3 years ago

Divid 15 into two parts such that the sum of their reciprocal is 3/10

Klio2033 [76]

From the information obtained from the question, two equations can be created:

Let x and z be the two numbers (parts)

$\frac{1}{z} + \frac{1}{x} = \frac{3}{10}$ . . . . (1)

$z + x = 15$ . . . . (2)

By transposing (2), make 'z' the subject of the equation
$z = 15 - x$ . . . . (3)

By substituting (3) into equation (1) to find a value for x
$\frac{1}{(15 - x)} + \frac{1}{x} = \frac{3}{10}$

$\frac{15}{( 15 - x ) ( x )} = \frac{3}{10}$

$3 ( - x^{2} + 15 x ) = 150$

$3 x^{2} - 45x + 150 = 0$

⇒ $( x - 5 ) ( x - 10 ) = 0$

∴ either $( x - 5) = 0$ OR $( x - 10 ) = 0$

Thus x = 5 or x = 10

By substituting the values of x into (2) to find z

z + (5) = 15 OR z + (10) = 15

⇒ z = 10 OR z = 5

So, the two numbers or two parts into which fifteen is divided to yield the desired results are 5 and 10.

5 0

3 years ago

Can someone answer this‼️‼️Give an equation for each answer and please read the directions for number 8 fill in Iceland and Hono

Dmitrij [34]

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5 0

3 years ago