Question

What are the solutions for x when y is equal to 0 in the following quadratic

Answer 1

Answer:

D) x = -12 or x = 2

Step-by-step explanation:

The given quadratic equation is:

$y=x^2+10x-24$

When y=0, we obtain:

$x^2+10x-24=0$

We split the middle term with -2, 12 because their product is is -24 and their sum is 10.

$x^2-2x+12x-24=0$

We factor by grouping to obtain:

$x(x-2)+12(x-2)=0$

$(x-2)(x+12)=0$

Either $(x-2)=0$ or $(x+12)=0$

Either $x=2$ or $x=-12$