Answer:
Interquartile Range
Step-by-step explanation:
i think
Answer: 0.9088
Step-by-step explanation:
Given : ![\mu=0.30](https://tex.z-dn.net/?f=%5Cmu%3D0.30)
Let x be a random available that represents the proportion of students that reads below grade level .
Using
, for x= 0.36 , we have
Using standard normal z-value table,
P-value
[Rounded yo the nearest 4 decimal places.]
Hence, the probability that a second sample would be selected with a proportion less than 0.36 = 0.9088
Just add the two equations together.
2b = 18
b = 18/2
b = 9
9 = k + 10
9 - 10 = k
k = - 1
<u>Given</u>:
It is given that the coordinates of the function are ![f=\{(-5,1),(-4,0),(0,6)\}](https://tex.z-dn.net/?f=f%3D%5C%7B%28-5%2C1%29%2C%28-4%2C0%29%2C%280%2C6%29%5C%7D)
We need to determine the value of f(0)
<u>Value of f(0):</u>
The value of f(0) is the value of the function when the input is 0.
We need to determine the value of f(0) when the input is x = 0
Thus, from the coordinates of the function
, it is obvious that the input value of the function is x = 0 , then the value of the function f(0) = 6.
Thus, when the input value x = 0, the output is f(0) = 6.
Therefore, the value of f(0) = 6.
Answer:
17.28
Step-by-step explanation: