The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
i do not know sorry for that Step-by-step explanation:
Answer:
50.24
Step-by-step explanation:
1/4x3.14xr^2
r=16 because of the length
90/360= 1/4
so
1/4x3.14x16^2/4
=50.24
4 is our denominator because of the denominator on the fraction
Answer:
0I do not know
Step-by-step explanation:
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