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Fittoniya [83]
3 years ago
6

A pea plant that is heterozygous for inflated pea pods is crossed with another plant that makes constricted pea pods. what are t

he F1 genotypic and phenotypic ratios? what is the probability that the offspring produce inflated pods?
Biology
1 answer:
Musya8 [376]3 years ago
3 0
50% of the offspring will make constricted pods and 50% will be inflated. the probability of inflated pods are 50% out of 100
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The ability of the human body to break down the red color in beets is controlled by an autosomal dominant allele. The inability
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Explanation:

<em>Let the ability to break down the red color in beets be represented by the allele </em><em>B</em><em>. The inability would be represented by the allele </em><em>b</em><em>.</em>

A nonsecretor's genotype would be BB or Bb while a secretor's genotype would be bb.

A nonsecretor woman with a secretor father would be a carrier with genotype Bb. A nonsecretor man who in a previous marriage had a secretor daughter would also be a carrier with genotype Bb. If the two marries:

            <em>Bb     x     Bb</em>

<em>            BB    2Bb    bb</em>

1.

(a) probability of their first child will be a secretor girl = probability of having a girl and being a secretor.

Probability of having a girl = 1/2

Probability of being a secretor = 1/4

<em>probability of their first child will be a secretor girl</em> = 1/2 x 1/4 = 1/8

(b) Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor.

Probability of having a girl = 1/2

Probability of being a nonsecretor = 3/4

<em>Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor</em> = 1/2 x 3/4 = 3/8

2. <em>Probability that their first two children will be nonsecretors of either sex = probability of their first being a nonsecretor and of either sex and probability of their second being a nonsecretor and of either sex.</em>

  = 3/4 x 3/4 = 9/16

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