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trasher [3.6K]
3 years ago
5

What is the pattern? 1,1 / 2,3 / 3,6 / 4,10 / 5,15. (x,y). Whoever answers gets brainliest!

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0
I’m not sure how to describe it but it seems like x will always go +1 and y will always go 1 higher than the last. So 1,1 = x +1, y +2. 2,3 = x +1, y +3.
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Helppp 1-7 ANSWERS help me get them ASAP
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Answer:

I can't see the graph.....

Step-by-step explanation:

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3 years ago
If the discriminant is negative then the quadratic has
zepelin [54]

Answer:

No <em>real</em> solutions (or has two complex roots)

Step-by-step explanation:

The discriminant, <em>b</em>² - 4<em>ac</em>, is the expression (<u><em>radicand </em></u>) of the quadratic equation:

x = \frac{-b +/- \sqrt{b^{2}-4ac} }{2a}.

The value of the discriminant determines the <u>nature</u> and the <u>number of solutions</u> given by the quadratic equation.

A discriminant with a negative value (or b² - 4ac < 0 ) means that the quadratic equation has no real solutions or two complex solutions. Quadratic equations with a negative discriminant also have no x-intercepts; thus, its graph will not cross the x-axis.  

4 0
3 years ago
plssssss awnser sooooonnnnn i really need this done fast! 25 points and brainliest if its right and pls dont put a dumb awser li
stich3 [128]

Answer:

I think that the altimeter would read as '0'. Positive readings would show that she was above sea level and negative readings we would show that she was below sea level. I hope that this helps

5 0
3 years ago
Solve the system by substitution.<br> -2x + 7y = 15<br> бу = 3
Salsk061 [2.6K]

Answer:

Step-by-step explanation:

-2x + 7(1/2) =15

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6 0
3 years ago
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
2 years ago
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