All categories

3 years ago

What is the pattern? 1,1 / 2,3 / 3,6 / 4,10 / 5,15. (x,y). Whoever answers gets brainliest!

1 answer:

4 0

I’m not sure how to describe it but it seems like x will always go +1 and y will always go 1 higher than the last. So 1,1 = x +1, y +2. 2,3 = x +1, y +3.

You might be interested in

Helppp 1-7 ANSWERS help me get them ASAP

NNADVOKAT [17]

Answer:

I can't see the graph.....

Step-by-step explanation:

5 0

3 years ago

If the discriminant is negative then the quadratic has

zepelin [54]

Answer:

No real solutions (or has two complex roots)

Step-by-step explanation:

The discriminant, b² - 4ac, is the expression (radicand ) of the quadratic equation:

$x = \frac{-b +/- \sqrt{b^{2}-4ac} }{2a}$ .

The value of the discriminant determines the nature and the number of solutions given by the quadratic equation.

A discriminant with a negative value (or b² - 4ac < 0 ) means that the quadratic equation has no real solutions or two complex solutions. Quadratic equations with a negative discriminant also have no x-intercepts; thus, its graph will not cross the x-axis.

4 0

3 years ago

plssssss awnser sooooonnnnn i really need this done fast! 25 points and brainliest if its right and pls dont put a dumb awser li

stich3 [128]

Answer:

I think that the altimeter would read as '0'. Positive readings would show that she was above sea level and negative readings we would show that she was below sea level. I hope that this helps

5 0

3 years ago

Solve the system by substitution. -2x + 7y = 15 бу = 3

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

-2x + 7(1/2) =15

-4x +7 =30

-4x =23

x=-23/4

6 0

3 years ago

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon

fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that $n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0

2 years ago