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natka813 [3]
3 years ago
6

How does the area of triangle RST compare to the area of triangle LMN?

Mathematics
2 answers:
RUDIKE [14]3 years ago
6 0

Answer:

The answer is the letter B or The area of △RST is equal to the area of △LMN.

Step-by-step explanation:


n200080 [17]3 years ago
6 0

Answer:

The correct option is 2. The area of △RST is equal to the area of △LMN.

Step-by-step explanation:

If three vertices of a triangle are given, then the area of triangle is

A=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|

The vertices of triangle RST are R(5,5), S(2,1), T(1,3).

The area of △RST is

A=\frac{1}{2}|5(1-3)+2(3-5)+1(5-1)|

A=\frac{1}{2}|-10-4+4|

A=\frac{10}{2}

A=5

The area of △RST is 5 square unit.

The vertices of triangle LMN are L(0,-1), M(2,-4), N(-2,-3).

A=\frac{1}{2}|0(-4+3)+2(-3+1)-2(-1+4)|

A=\frac{1}{2}|-4-6|

A=\frac{10}{2}

A=5

The area of △LMN is 5 square unit.

The area of △RST is equal to the area of △LMN, therefore the correct option is 2.

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In circle o, the length of radius OL is 6 cm and the length
AlekseyPX

Answer:

14.2cm

Step-by-step explanation:

The diagram representing the circle and its attributes has been attached to this response.

<em>As shown in the diagram;</em>

The circle is centered at o,

The length of radius OL = 6cm

The length of the arc LM = 6.3cm

The angle MON = 75°

The angle LOM = θ

<em>Remember that;</em>

The length, L, of an arc is given by;

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Where;

θ is the angle subtended by the arc

r = radius of the circle.

Using the formula in equation (i), let's calculate the angle θ subtended by arc LM as follows;

L = (θ / 360) x (2πr)  

Where;

L = length of arc LM = 6.3cm

r = radius of the circle = length of radius OL = 6cm

<em>Substitute these values into the equation to get;</em>

6.3 = (θ / 360) x (2 x π x 6)

6.3 = (θ / 360) x (12 x π)

6.3 = (θ / 30) x (π)              [Take π = 22/7]

6.3 = (θ / 30) x (22 / 7)

θ = \frac{6.3*30*7}{22}

θ = 60.14°

Therefore, the angle subtended by arc LM is 60.14°

Now, from the diagram,

The angle subtended by arc LMN is;

θ + 75° = 60.14° + 75° =  135.14°

Let's now calculate the length of arc LMN using the same equation (i)

L = (θ / 360) x (2πr)  

Where;

L = length of arc LMN

θ = angle subtended by LMN = 135.14°

r = radius of the circle = length of radius OL = 6cm

<em>Substitute these values into the equation;</em>

L = (135.14° / 360°) x (2 x π x 6)             [Take π = 22/7]

L = 14.15cm

Therefore, the length of arc LMN is 14.2cm to the nearest tenth.

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