Answer:
See explanation
Step-by-step explanation:
1. The given function is

The domain values are: x=0, 2, -1, 4, -2
When x=0

When x=2,

When x=-1

When x=4

When x=-2

2. The given function is

When x=3,

Similarly,




Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
Answer:
a = 2500mm
b = 5km
c = 2e+7
Step-by-step explanation:
Answer:
Area of a rectangle = 7/12 of an inch
Step-by-step explanation
Area of a rectangle = Length × width
In this case, the length is represented by height
Height = 2/3 of an inch
Width = 7/8 of an inch
Area of a rectangle = Length × width
= 2/3 × 7/8
= (2 * 7) / (3 * 8)
= 14 / 24
= 7 / 12
Area of a rectangle = 7/12 of an inch
Answer:
huh? -1 is a decimal number maybe write it as -1.0 ?